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marissa [1.9K]
3 years ago
6

Wegener's claim was that the continents drifted from their original positions in Pangea

Chemistry
1 answer:
steposvetlana [31]3 years ago
7 0

Answer:

Imagine that you are a farmer in ancient Egypt. You must carefully plan around the flooding of the Nile in order to raise your crops.

Starting with planting (number 1), use the numbers 1 - 5 to place the following events in the correct order.

1 The floodwater recedes and you plant your crops.

The Nile begins to rise.

The Nile Valley is flooded again.

The hot season begins, and the Nile begins to dry up.

You harvest your crops

Explanation:

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The atomic number of Re is 75. The atomic mass of one of its isotopes is 186. How many neutrons are in an atom of this isotope?
USPshnik [31]

Answer:

B.111

Explanation:

Atomic mass = number of protons(or atomic number) + number of neutrons

186 = 75 + number of neutrons

number of neutrons = 186 -75 = 111

7 0
3 years ago
Convert 5° C into Fahrenheit.
Lady_Fox [76]

Answer:

5 in celcius is 41 in fahrenheit!

Explanation:

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3 years ago
1. Which of the following best describes the relationship
Ipatiy [6.2K]
D there is one kind of cell of which all living things are made
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3 years ago
A chemical formula written above or below the yield sign indicates:
sweet-ann [11.9K]
I believe the correct answer from the choices listed above is option B. A chemical formula written above or below the yield sign indicates <span>that the substance is used as a catalyst. I am certain with this answer. Hope this helps. Have a nice day.</span>
3 0
3 years ago
Read 2 more answers
A Silty Clay (CL) sample was extruded from a 6-inch long tube with a diameter of 2.83 inches and weighed 1.71 lbs. (a) Calculate
inna [77]

Answer:

a) the wet density of the CL sample is 0.0453 lb/in³

b) the water content in the sample is 65.37%

c) the dry density of the CL sample is 0.0274 lb/in³

Explanation:

Given that;

diameter d = 2.83 in

length L = 6 in

weight m = 1.71 lbs

A piece of clay sample had wet-weight of 140.9 grams  and dry-weight of 85.2 grams

a) wet density of the CL sample

wet density can be expressed as  p = M /v

V is volume of sample which is; π/4×d²×L

so p = M / π/4×d²×L

we substitute

p = 1.71 / (π/4 × (2.83)²× 6

p = 1.71 / 37.741

p = 0.0453 lbs/in³

so the wet density of the CL sample is 0.0453 lb/in³

b)

water content of sample is taken as;

w =  (wet_weight - dry_weight) / dry_weight

we substitute

w = (140.9 - 85.2) / 85.2

w = 55.7 / 85.2

w = 0.6537 = 65.37%

therefore the water content in the sample is 65.37%

c)

dry density of the CL sample

to determine the dry density, we say;

Sd = p / ( 1 + w )

we substitute

Sd = 0.0453 / ( 1 + 0.6537)

Sd = 0.0453 /  1.6537

Sd = 0.0274 lb/in³

therefore the dry density of the CL sample is 0.0274 lb/in³

8 0
3 years ago
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