Answer:
The sum of first five term of GP is 19607.
Step-by-step explanation:
We are given the following in the question:
A geometric progression with 7 as the first term and 7 as the common ration.
![a, ar, ar^2,...\\a = 7\\r = 7](https://tex.z-dn.net/?f=a%2C%20ar%2C%20ar%5E2%2C...%5C%5Ca%20%20%3D%207%5C%5Cr%20%3D%207)
![7, 7^2, 7^3, 7^4...](https://tex.z-dn.net/?f=7%2C%207%5E2%2C%207%5E3%2C%207%5E4...)
Sum of n terms in a geometric progression:
![S_n = \displaystyle\frac{a(r^n - 1)}{(r-1)}](https://tex.z-dn.net/?f=S_n%20%3D%20%5Cdisplaystyle%5Cfrac%7Ba%28r%5En%20-%201%29%7D%7B%28r-1%29%7D)
For sum of five terms, we put n= 5, a = 7, r = 7
![S_5 = \displaystyle\frac{7(7^5 - 1)}{(7-1)}\\\\S_5 = 19607](https://tex.z-dn.net/?f=S_5%20%3D%20%5Cdisplaystyle%5Cfrac%7B7%287%5E5%20-%201%29%7D%7B%287-1%29%7D%5C%5C%5C%5CS_5%20%3D%2019607)
The sum of first five term of GP is 19607.
Verification:
![2801\times 7 = 19607](https://tex.z-dn.net/?f=2801%5Ctimes%207%20%3D%2019607)
Thus, the sum is equal to product of 2801 and 7.
It equal to 24 because you have to multiply or divide first then you can add or subtract
I think 0.3 is less 7.85 because there is a 1 on the end that was is a 3 and if you round it would be 0
Answer:
z = 66
Step-by-step explanation:
QT is a midsegment. Thus, applying the midsegment theorem:
RS = 2(QT)
QT = z - 33,
RS = z
Plug in the values into the equation
z = 2(z - 33)
z = 2z - 66
Subtract 2z from each side
z - 2z = -66
-z = -66
Divide both sides by -1
z = 66
1. 0.8
2. 3.87298
3. ?
4. ?
5. ?
6. 5
7. True
8. ?
9.