Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Answer:
14 3/8 pounds
Step-by-step explanation:
6 pounds plus 8 pounds= 14 pounds. 1/4 + 1/8= 3/8. 1/4 can be turned into 2/8, and 2/8 plus 1/8 equals 3/8. Hope this helps :)
Given :
Two equations :
-8x + 3y = -17 ....1)
3x - y = 7 ....2)
To Find :
The solution of the system.
Solution :
Multiplying equation 2) by 3 and adding with equation 1), we get :
(-8x + 3y) + 3(3x - y) = -17 + 21
x = 4
Putting above value of x equation 2) we get :
12 - y = 7
y = 5
Therefore, solution of system is ( 4,5 ).
Remember: We have to work from either the LHS or the RHS.
(Left hand side or the Right hand side)
You should already know this:

You should also know this:

So plugging in both of those into our identity, we get:

Simplify the denominator on the LHS (Left Hand Side)
We get:

LHS = RHS
Therefore, identity is verified.
Answer:
B? I think
Step-by-step explanation:
sorry I really want to help but I dont get what the question is asking