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3 years ago

The area of a circle is 100pi square inches. What is the circumference

Mathematics

1 answer:

lara31 [8.8K]3 years ago

3 0

Answer:

the cercomference is 220

Step-by-step explanation:

You might be interested in

What is the length of this pool? 6 ft X 97 5 ft

svetlana [45]

Answer:

I think it's 2,910 ft

Step-by-step explanation:

I did 6 times 97 times 5 to get the answer

3 0

3 years ago

The oil prices for 2014, rounded to the nearest dollar, were: 95, 101, 101, 102, 102, 106, 104, 97, 93, 84, 76, 59. what is the

kipiarov [429]

Interquartile Range (IQR) = $Q_3-Q_1$ , with $Q_3$ as the upper quartile and $Q_1$ as the lower quartile.

Firstly, rearrange the data so that it's in ascending order: $\{59,76,84,93,95,97,101,101,102,102,104,106\}$

Next, find the median:

$\{59,76,84,93,95,\boxed{97,101,}101,102,102,104,106\}\\\\\frac{97+101}{2}\\\\\frac{198}{2}\\\\99$

Now to find the lower quartile, find the "median" of the data set that's to the left of 99:

$\{\overbrace{59,76,84,93,95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\{\overbrace{59,76,\boxed{84,93}95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\frac{84+93}{2}\\\\\frac{177}{2}\\\\88.5$

Now to find the upper quartile, it's the similar process as finding the lower quartile, except that you are finding the "median" of the data set to the right of 99:

$\{59,76,84,93,95,97,\overbrace{101,101,102,102,104,106}^{\textsf{to the right of the median}}\}\\\\\{59,76,84,93,95,97,\overbrace{101,101,\boxed{102,102} 104,106}^{\textsf{to the right of the median}}\}\\\\\frac{102+102}{2}\\\\\frac{204}{2}\\\\102$

Now that we have the upper and lower quartile, subtract them:

$102-88.5=13.5$

In short, the IQR of this data set is 13.5.

8 0

3 years ago

An experiment involves 16 participants. From these, a group of 4 participants is to be tested under a special condition. How man

zheka24 [161]

Answer:

43,680 ways.

Step-by-step explanation:

We have been given that an experiment involves 16 participants. From these, a group of 4 participants is to be tested under a special condition. We are asked to find the number of groups of 4 participants that can be chosen, assuming that the order in which the participants are chosen is irrelevant.

We will use permutations formula to solve our given problem.

$^nP_r=\frac{n!}{(n-r)!}$

For our given problem $n=16$ and $r=4$ .

$^{16}P_4=\frac{16!}{(16-4)!}$

$^{16}P_4=\frac{16!}{12!}=\frac{16*15*14*13*12!}{12!}=16*15*14*13=43,680$

Therefore, 4 participants can be chosen in 43,680 different ways.

6 0

4 years ago

The quantity demanded x each month of Russo Espresso Makers is 250 when the unit price p is $138. The quantity demanded each mon

Stells [14]

Answer:

(a) $D(q)=\frac{-1}{25} q+148$

(b) $S(q)=\frac{1}{50}q+58$

Step-by-step explanation:

(a) For the demand equation D(q) we have

P1: 138 Q1: 250

P2: 108 Q2: 1000

We can find m, which is the slope of the demand equation,

$m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{108-38}{1000-250} =\frac{-30}{750}=\frac{-1}{25}$

and then we find b, which is the point where the curve intersects the y axis.

We can do it by plugging one point and the slope into the line equation form:

$y=mx+b\\\\D(q)=mq+b\\\\138=\frac{-1}{25}(250) +b\\\\138=-10+b\\\\138+10=b=148$

With b: 148 and m: -1/25 we can write our demand equation D(q)

$D(q)=\frac{-1}{25} q+148$

(b) to find the supply equation S(q) we have

P1: 102 Q1: 2200

P2: 102 Q2: 700

Similarly we find m, and b

$m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{72-102}{700-2200} =\frac{-30}{-1500}=\frac{1}{50}$

$y=mx+b\\\\D(q)=mq+b\\\\72=\frac{1}{50}(700) +b\\\\72=14+b\\\\72-14=b=58\\$

And we can write our Supply equation S(q):

$S(q)=\frac{1}{50}q+58$

(c) Now we may find the equilibrium quantity q* and the equilibrium price p* by writing D(q)=S(q), which means the demand equals the supply in equilibrium:

$D(q)=S(q)\\\\\frac{-1}{25}q+148=\frac{1}{50}q+58\\\\$

$148-58=\frac{1q}{50} +\frac{1q}{25} \\\\90= \frac{1q}{50} +\frac{2q}{50}\\\\90=\frac{3q}{50}\\ \\q=1500\\\\$

We plug 1500 as q into any equation, in this case S(q) and we get:

$S(q)=\frac{1}{50}q+58\\\\S(1500)=\frac{1}{50}(1500)+58\\\\S(1500)=30+58\\\\S(1500)=88$

Which is the equilibrium price p*.

8 0

3 years ago

En el mercado del satisfactor X hay 10,000 individuos idénticos, cada uno con una función de demanda definida por Qdx = 12 – Px

shepuryov [24]

Answer:

Px = $4

Step-by-step explanation:

Given that:

En el mercado de satisfacción X hay 10,000 individuos idénticos, cada uno con una función de demanda definida por Qdx = 12 - Px y 1,000 productores idénticos de X satisfactorio, cada uno con una función de oferta dada por Qsx = 20 Px

El precio de equilibrio y la cantidad de equilibrio se pueden determinar de la siguiente manera;

Qdx = 10000(12-Px)

Qdx = 120000 - 10000Px

Qsx = 1000(20 Px)

Qsx = 20000 Px

El punto de equilibrio para completar el enunciado, cuando Qdx = Qsx es:

Qdx = Qsx

120000 - 10000 Px = 20000 Px

120000 = 20000 Px + 10000 Px

120000 = 30000 Px

Px = $\mathbf{ \dfrac{120000}{30000}}$

Px = $4

7 0

4 years ago