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Lelu [443]
3 years ago
6

PROBLEM 6

Mathematics
1 answer:
Inessa [10]3 years ago
8 0

Answer:

See below.

Step-by-step explanation:

The nth triangular number is Tn = n(n + 1)/2, the nth square number Qn = n^2 and the nth pentagonal number Pn = (3n^2 - n) / 2.

(a.  Q6 + P5 = 6^2 + (3(5)^2 - 5)/2

= 36 + 35 = 71.

3T5 + Q5 + 1 =   3* 5(5 + 1) / 2 + 5^2 + 1

= 90 / 2 + 26

= 71.

So  Q6 + P5 = 3T5 +Q5 +1.

(b) Qn+1 + Pn  = (n + 1)^2 + (3n^2 - n) / 2

=  n^2 + 2n + 1 + (3n^2 - n) / 2

= n^2 + 2n + 1  + 1.5n^2 - 0.5n

= 2.5n^2 + 1.5n + 1.

3Tn +Qn + 1 = 3n(n + 1) / 2  + n^2 + 1

=  3n^2 + 3n / 2 + n^2 + 1

= 1.5n^2 + 1.5n + n^2 + 1

= 2.5n^2 + 1.5n + 1.

Therefore they are equal for all positive n.

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Which of the following situations does NOT illustrate combination?
Gemiola [76]

Answer:

Step-by-step explanation:

Permutation and combination is very important in our daily life. By using it, we can already distinguish or identify the different possible ways of the things that we get or have.

Permutation refers to the different possible arrangements of a set of objects and order is very important while combination is the number of ways of selecting from a set when the order is not important.

Which of the following situations does NOT illustrate combination?

a. Selecting 2 songs from 10 choices for an audition piece

b. Fixing the schedule of a group of students who must take exactly 8 subjects

c. Enumerating the subsets of a set

d. Identifying the lines formed by connecting some given points on a Plane

In this situations, we can determine if it is all combination or not. Let's find it out.

a. Selecting 2 songs from 10 choices for an audition piece - this situation does not require any order or arrangement. That's why letter A illustrates combination.

b. Fixing the schedule of a group of students who must take exactly 8 subjects - in fixing and arranging the schedule of a group of students, it must have to be in order so that they can determine their subjects every hour or period and everyday. The schedule must be arrange properly so that the students must not get confused. That's why in this situation the order and arrangement is very important and it shows the concept of permutation not combination.

c. Enumerating the subsets of a set - in enumerating we are not required to make it in order. We can list the subsets of a set in any order, that's why letter C illustrates combination.

d. Identifying the lines formed by connecting some given points on a Plane - we can connect different and many given points in any directions to have a Plane. It is not required to connect all the points in order so that we can form a Plane. Also, in identifying the lines, we can write and list it in any order and that the order is not important.

In conclusion, the situation that does NOT illustrate combination is situation B, because it is more on the concept of permutation not in combination.

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