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Andrej [43]
3 years ago
8

Given the function f(x) = 5(x+4) − 6, solve for the inverse function when x = 19.

Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0

Answer:

The answer is 1 i.e the inverse function will be 1 when x=19

Step-by-step explanation:

Given f(x)=5(x+4)-6

we have to solve for inverse function

Step 1: Replace f(x) with y.

              y=5(x+4)-6

Step 2: Now replace all x with y and all y with x, we get

              x=5(y+4)-6

Step 3: Solve for y

    x+6=5(y+4)

 ⇒         x+6=5y+20

 ⇒         x+6-20=5y

 ⇒         y=\frac{x-14}{5}

Step4: Replace y by f^{-1}(x)

gives     f^{-1}(x)=\frac{x-14}{5}

When x=19      (given)

⇒ f^{-1}(x)=\frac{19-14}{5}=1


vlada-n [284]3 years ago
4 0
Y = 5(x+4)-6 
x = 5(y+4)-6 
x = 5y +20 - 6 
x= 5y +14 
5y = x-14 
y = (x-14)/5 
<span>
when x = 19, y = (19-14)/5 </span>
y = 5/5 
<span>y=1

In short, Your Answer would be Option 2

Hope this helps!</span>
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How many tenths make up 4 wholes?<br>​
NikAS [45]

Divide 4 by 1/10.

So, 4 ÷ 1/10 becomes 4 x 10/1.

We know that 4 x 10/1 = 40/1 = 40.

Did you follow?

6 0
3 years ago
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Ab=45 mm,bc=10cm 4mm ,cd = 5 cm 6 mm ,de= 35 mm,ea=x cm, and the perimeter of irregular pentagon is 280 mm. Find the length of t
DaniilM [7]

Answer:

The length of the unknown side x is 4 cm

Step-by-step explanation:

we know that

The perimeter of a polygon is equal to the sum of its length sides

Remember that

1 cm=10 mm

In this problem we have

AB=45 mm ------> convert to cm -----> AB=45/10=4.5 cm

BC=10 cm 4 mm -----> convert to cm -----> BC=10+4/10=10.4 cm

CD=5 cm 6 mm  -----> convert to cm -----> CD=5+6/10=5.6 cm

DE=35 mm ------> convert to cm -----> DE=35/10=3.5 cm

EA=x cm

P=280 mm ------> convert to cm -----> P=280/10=28 cm

The perimeter of the irregular polygon is equal to

P=AB+BC+CD+DE+EA

substitute the values

28=4.5+10.4+5.6+3.5+x

28=24+x

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3 0
3 years ago
Which statements about the local maximums and minimums for the given function are true? Choose three options.
Nostrana [21]

Answer:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

This is a false statement. Look at the graph. The minimum point given is (3.4,-8). Therefore the local minimum is -8 not 0

Over the interval [2, 4], the local minimum is –8.

This statement is true because the given minimum point is(3.4, -8). Thus the  local minimum is -8 which is true

Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum  is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

This is a false statement because there is no maximum point

8 0
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