Answer:
Step-by-step explanation:
Consider the selling of the units positive earning and the purchasing of the units negative earning.
<h3>Case-1:</h3>
- Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
- Mr.A earns Rs6000
So, the equation would be
<h3>Case-2:</h3>
- Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
- Mr B neither lose nor gain meaning he has made 0₹
hence,
<h3>Case-3:</h3>
- Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
- Mr.C earns 13000₹
therefore,
Thus our system of equations is
<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>
we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:
Now solve the equation accordingly:
Solving the equation for x and y yields:
plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,
Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437
Let gradient of original line = m = 1/6
Gradient of line perpendicular to this = -1/m = -6
(Gradient = slope)
Answer:
1by 2 into3 by 5 multiply
Answer:
Infinitely many solutions.
Explanation:
In this case we gonna use ELIMINATION BY ADDITION method.For that first we are gonna eliminate the terms containing ( X ).
Equation no 1:
3x + 3y = 10
Equation no 2:
-9x - 9y = -30
Now multiply equation no 1 with (3 )
3(3x + 3y) = 3(10)
9x + 9y = 30 ( equation no 1 )
Now ADD both the equations
9x + 9y = 30
<u> -9x - 9y =-30</u>
0 = 0