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Fittoniya [83]
3 years ago
11

1. Which of the following measurements could be the three side lengths of a right triangle? a. 4 cm, 5 cm, 9 cm b. 12 cm, 20 cm,

25 cm c. 18 cm, 24 cm, 30 cm d. 2 cm, 3 cm, 5 cm
Mathematics
1 answer:
HACTEHA [7]3 years ago
8 0

Answer:

b and c

Step-by-step explanation:

The Triangle Inequality Theorem lets us know that the sum of the two shortest sides of the triangle must be greater than the third side of the triangle.

In both A and D, the sum of the shortest two sides are equal to, not greater than the third side, so they will not form a triangle.

In B, 12+20 is 32, which is greater than 25. And in C, 18+24 is 42, which is greater than 30, so they both will form a triangle.

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Find the value of x. round your answer to the nearest tenth.
Yakvenalex [24]

9514 1404 393

Answer:

  x ≈ 13.7

Step-by-step explanation:

The relevant trig relation is ...

  Tan = Opposite/Adjacent

  tan(58°) = 22/x

  x = 22/tan(58°) ≈ 13.747

The value of x is about 13.7 units.

5 0
3 years ago
Juan received a bank account statement reporting the recent changes
Flura [38]

Answer:

2628.15

Step-by-step explanation:

1909.15+ 1437.99/2=2628.15

3 0
3 years ago
A rectangular container measuring 20 inches long by 16 inches wide by 12 inches tall is filled to its brim with water. If 850 cu
makkiz [27]

The new height of the water is = 9.34 inches (approx)

Step-by-step explanation:

Given, a rectangular container measuring 20 inches long by 16 inches wide by 12 inches tall is filled to its brim with water.

Let the new height of water level be x inches.

The volume of the container = (20×16×12) cubic inches

                                               =3840  cubic inches

According to the problem,

3840 - (20×16×x) = 850

⇔3840 -320x = 850

⇔-320x =850-3840

⇔-320 x = -2990

\Leftrightarrow x =\frac{2990}{320}

⇔x = 9.34 inches

The new height of the water is = 9.34 inches (approx)

5 0
2 years ago
Please help!!!!!!!!!!
defon

Answer: 90 + 4, third choice   and    90 - -4, last choice

Her score is obviously higher when the mistake is fixed, adding the 4 points gives 94.

3 0
2 years ago
Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B
Tems11 [23]

Answer:

0.75

Step-by-step explanation:

Given,

P(A) = 0.6, P(B) = 0.4, P(C) = 0.2,

P(A ∩ B) = 0.3, P(A ∩ C) = 0.12, P(B ∩ C) = 0.1 and P(A ∩ B ∩ C) = 0.07,

Where,

A = event that the selected student has a Visa card,  

B = event that the selected student has a MasterCard,  

C = event that the selected student has an American Express card,

We know that,

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)

= 0.6 + 0.4 + 0.2 - 0.3 - 0.12 - 0.1 + 0.07

= 0.75

Hence, the probability that the selected student has at least one of the three types of cards is 0.75.

5 0
2 years ago
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