Answer:
<u>Constructive interference defination:</u>
''Constructive interference occurs when the maxima of two waves add together (the two waves are in phase), so that the amplitude of the resulting wave is equal to the sum of the individual amplitudes''
Constructive interference occurs at integer multiples of the wavelength of the wave. The lowest incidence occurs at the wavelength.
<em>As we know,</em>
wavelength * frequency = velocity
wavelength = v/f
= (343 m/s) / (220 1/s)
= 1.56 m
_ acceleration occurs when an object speeds up.
Answer
Positive
Explanation:
We can solve the problem, either using graph or equation, as per our liking :
u = 12 m/s
v = - 8 m/s
t = 5 sec
(1) v = u + at
-8 = 12 + 5a
<u>a = - 4 m/s^2 </u>
<u>(</u><u>2</u><u>)</u> S = ut + 1/2 * a * t^2
S = 12 * 5 - 2 * 25
<u>S (Distance travelled) = 10 m</u>
Answer:
139
Explanation:
sorry if its wrong yyyyyeeeeeeeeeeaaaaaahhhhhhbbbbbbbooooiiiiiiiiiiiii
Answer:
19 contraction cycles could theoretically be fueled by the complete combustion of one mole of glucose.
Explanation:
Complete Question
Assume that the complete combustion of one mole of glucose to carbon dioxide and water liberates 2870 kJ/mol.
One contraction cycle in muscle requires 67 kJ, and the energy from the combustion of glucose is converted with an efficiency of 45% to contraction, how many contraction cycles could theoretically be fueled by the complete combustion of one mole of glucose? Round your answer to the nearest whole number.
Complete combustion of glucose liberates 2870 kJ/mol.
Complete combustion of one mole of glucose will liberate 2870 × 1 = 2870 kJ
The energy from the combustion of glucose is converted with an efficiency of 45% to contraction.
So, the amount of energy from the combustion of one mole of glucose that is converted to contraction is
45% × 2870 = 1,291.5 kJ
One contraction cycle requires 67 kJ of energy, so, 1291.5 kJ will cause
(1291.5/67) contraction cycles = 19.28 contraction cycles = 19 contraction cycles to the nearest whole number.
Hope this Helps!!!