Answer:
a) a = 1,865 m / s² and b) t = 8.1 s
Explanation:
a) Let's use Newton's second law to find acceleration, we can work the equation in scalar form because displacement and force have the same direction
F = m .a
a = F / m
a = 8.02 10² /4.3 10²
a = 1,865 m / s²
b) We use kinematic relationships in one dimension
vf = vo + at
vf = 0 + a t
t = vf / a
t = 15.1 / 1.865
t = 8.1 s
Answer:
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Explanation:
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Explanation:
Given Data
Total mass=93.5 kg
Rock mass=0.310 kg
Initially wagon speed=0.540 m/s
rock speed=16.5 m/s
To Find
The speed of the wagon
Solution
As the wagon rolls, momentum is given as
P=mv
where
m is mass
v is speed
put the values
P=93.5kg × 0.540 m/s
P =50.49 kg×m/s
Now we have to find the momentum of rock
momentum of rock = mv
momentum of rock = (0.310kg)×(16.5 m/s)
momentum of rock =5.115 kg×m/s
From the conservation of momentum we can find the wagons momentum So
wagon momentum=50.49 -5.115 = 45.375 kg×m/s
Speed of wagon = wagon momentum/(total mass-rock mass)
Speed of wagon=45.375/(93.5-0.310)
Speed of wagon= 0.487 m/s
Throwing rock backward,
momentum of wagon = 50.49+5.115 = 55.605 kg×m/s
Speed of wagon = wagon momentum/(total mass-rock mass)
speed of wagon = 55.605 kg×m/s/(93.5kg-0.310kg)
speed of wagon= 0.5967 m/s
