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3 years ago

What is the equivalent resistance of a circuit that contains two 50.00

Physics

2 answers:

tigry1 [53]3 years ago

5 0

Answer:

100.0

Explanation:

Whitepunk [10]3 years ago

4 0

Answer:

Explanation:

Resistors in series add. There is only one path the current can take. That's why Christmas Tree lights sometimes give a lot of trouble. If a bulb burns out, it could be any one of them and time is needed to find the burned out bulb.

That being the case R = R1 + R2

R1 = 50 ohms

R2 = 50 ohms

R = 50 + 50

R = 100 ohms

Answer A

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Answer:

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Explanation:

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3 years ago

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erastovalidia [21]

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3 years ago

You are 12 miles north of your base camp when you begin walking north at a speed of 2 miles per hour. What is your location, rel

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4 years ago

Read 2 more answers

Why do atoms form bonds by donating, accepting or sharing electrons with other atoms?

sineoko [7]

Answer:

atoms form bonds by donating, accepting or sharing electrons with other atoms in order to complete their valence shell electrons

hence , C. Bonding gives an atom the same number of protons as a noble gas.

Explanation:

i hope it helped

7 0

3 years ago

An aluminum wire having a cross-sectional area equal to 2.20 10-6 m2 carries a current of 4.50 A. The density of aluminum is 2.7

Kazeer [188]

Answer:

The drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.

Explanation:

We can find the drift speed by using the following equation:

$v = \frac{I}{nqA}$

Where:

I: is the current = 4.50 A

n: is the number of electrons

q: is the modulus of the electron's charge = 1.6x10⁻¹⁹ C

A: is the cross-sectional area = 2.20x10⁻⁶ m²

We need to find the number of electrons:

$n = \frac{6.022\cdot 10^{23} atoms}{1 mol}*\frac{1 mol}{26.982 g}*\frac{2.70 g}{1 cm^{3}}*\frac{(100 cm)^{3}}{1 m^{3}} = 6.03 \cdot 10^{28} atom/m^{3}$

Now, we can find the drift speed:

$v = \frac{I}{nqA} = \frac{4.50 A}{6.03 \cdot 10^{28} atom/m^{3}*1.6 \cdot 10^{-19} C*2.20 \cdot 10^{-6} m^{2}} = 2.12 \cdot 10^{-4} m/s$

Therefore, the drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.

I hope it helps you!

4 0

2 years ago