m1= mass 1 = 1.1 kg
Vi1 = initial velocity 1 = 2.7 m/s
m2= 2.4 kg
V2i = -1.9 m/s
We assume east as positive and west as negative.
Apply the formulas:
Vf1 = ?
Replacing:
Answer: 3.6 m/s west
The ball is traveling in the + x direction at 8m per second. After 20 seconds it has moved 160m forward from the spot where it was tossed.
Answer:
d ............................
Answer:
a) The wavelength of light is 6×10^-7 m.
b) The size of the central peak is 6×10^-3 m.
Explanation:
let:
α be the distance between the 1st and 2nd maxima
d = 0.4 mm be the grating slit space
X be the distance to the screen
a) α = λ×X/d
λ = α×d/X
= (0.3×10^-2)×(0.4×10^-3)/(2)
= 6×10^-7 m
Therefore, the wavelength of light is 6×10^-7 m.
b) the size of the central peak is given by:
D = 2×λ×X/d
= 2×(6×10^-7)×(2)/(0.4×10^-3)
= 6×10^-3 m
Therefore, the size of the central peak is 6×10^-3 m.
