Why is knowing the direction of the force important?

1 answer:

4 0

Knowing the direction of a force is important because it helps someone know the motion of the object. if you use a free body diagram, then it becomes easy to see all the forces being applied to an object. if there is more force going one way, the object is accelerating in that direction. if all the forces cancel each other out, then the object is at a constant speed or is at rest.

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Daniel wants to find out if he can notice the difference in light intensity when he adds some lit candles to a set of 50 lit can

nexus9112 [7]

Answer:

Explanation:

The light intensity may be defined as the strength of the light or the magnitude of its brightness that a source of light can produce.

The light threshold is the minimum intensity of the light that our eye can detect and the ability to adapt to darkness.

In the context, Daniel wishes to find if can notice the difference in the intensity of the light when he add 5 candles to the set of 50 candles.

He noticed that when he added 5 candles, he could notice the difference in the intensity and when he added less than 5 candles to the set of 50 candles he could not detect.

Thus, the difference threshold for Daniel to detect the change in the intensity of the light is 5 candles.

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A researcher finds that blood alcohol levels cause Progressive damage the liver all of mice and his study were fed the same amou

Juli2301 [7.4K]

Answer:hmm

Explanation:

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3 years ago

An object on the surface of the earth weights 90lb at three radii above the surface it will weigh

nikitadnepr [17]

Answer:

At 3 radii above surface, the scale would display 5.6lb.

Explanation:

An object that is said to weigh 90lb, has--due to the gravitational force at Earth's surface-- a gravitational weight of 40.8kg * 9.8 m/s^2 = 400N. This means it is pulled by the gravity toward the center of the Earth with a force of 400N. The gravity follows Newton's formula:

$F = G\frac{m_o\cdot m_E}{r^2}$

where G is an empirical constant mo is the mass of the object (NOT its "weight"), mE is mass of the Earth, and r is the radius from the center of the Earth. So we know that:

$G\frac{m_o\cdot m_E}{r^2}=400N$

and at a distance extended by 3 more r's it is going to be:

$G\frac{m_o\cdot m_E}{(4r)^2}=G\frac{m_o\cdot m_E}{16r^2}=x$

If you divide both equations and isolate x you will conclude that the gravity at 3 radii above the surface will be 400/16, or 16 times smaller. That would be the clean answer - the gravity (measure in Newtons) will be 25N. If you use the same scale to proclaim the "weight" in pounds, you will observe that the measurement of 90lb will become also 16 times smaller, or about 5.6lb, which would be the answer to the question as posted. Please note that weight should not be mixed up with mass, but the wording of this question is really not helping keeping things clean.

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3 years ago

Read 2 more answers

a hawk flies in a horizontal arc of radius 10.3 m at a constant speed of 4.8 m/s. find its centripetal acceleration. answer in u

n200080 [17]

The hawk’s centripetal acceleration is 2.23 m/s²

The magnitude of the acceleration under new conditions is 2.316 m/s²

radius of the horizontal arc = 10.3 m

the initial constant speed = 4.8 m/s

we know that the centripetal acceleration is given by

$a_{c}$ = $\frac{v^{2} }{r}$