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Dmitry [639]
3 years ago
14

Why is knowing the direction of the force important?

Physics
1 answer:
vodomira [7]3 years ago
4 0
Knowing the direction of a force is important because it helps someone know the motion of the object. if you use a free body diagram, then it becomes easy to see all the forces being applied to an object. if there is more force going one way, the object is accelerating in that direction. if all the forces cancel each other out, then the object is at a constant speed or is at rest.
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The intensity level of a "Super-Silent" power lawn mower at a distance of 1.0 m is 100 dB. You wake up one morning to find that
OLEGan [10]

Answer: The intensity level of sound in the bedroom is 80dB

Explanation:

Intensity of lawn mower at r=1m is 100dB

Beta1= 10dBlog(I1/Io)

100dB= 10dB log(I1/Io)

10^10= I1/Io

I1= Io(10^10)

10^12)×(10^10)= I1

I1=10^-2w/m^2

Intensity of lawn mower at r=20m

I2/I1=(r1/r2)^2 =(1/20)^2

I2= I1(1/400)

I2=2.5×10^-3W_m^2

Intensity of 4 lown mowers at 20m fro. Window

= 10dBlog(4I2/Io)

= 10^-4/10^-12

=80dB

6 0
3 years ago
A change from one form of energy into another is called
pantera1 [17]
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6 0
4 years ago
Read 2 more answers
How as the energy of infrared, visible light and ultraviolet rays related?and why
sleet_krkn [62]
All are forms of electromagnetic radiation. hope this helps!
5 0
3 years ago
Read 2 more answers
Homework help asap!!
ozzi
Where is the picture cant6 see it

7 0
4 years ago
The drum shown in the figure has a radius of 0.40 m and a moment of inertia of 2.3 kg • m2 about an axis perpendicular to it thr
Citrus2011 [14]

The constant force applied to the rope is 7.72 N.

<h3>Net torque on the drum</h3>

The net torque on the drum is calculated as follows;

Fr - F_fr = I \alpha

Linear speed, v = ωr = 23 x 0.4 = 9.2 m/s

distance traveled = 14 m

<h3>Tangential acceleration</h3>

The acceleration of the drum is calculated as follows;

v² = u² + 2as

v² = 0 + 2as

v² = 2as

a = v²/2s

a = (9.2)/2(14)

a = 0.329 m/s²

<h3>Angular acceleration of the drum</h3>

\alpha = \frac{a}{r} = \frac{0.329}{0.4} = 0.82  \ rad/s^2

<h3>Applied force</h3>

The constant force applied to the rope is calculated as follows;

Fr - F_fr = I \alpha\\\\Fr = I \alpha + F_fr\\\\F = \frac{ I \alpha + F_fr}{r} \\\\F = \frac{2.3(0.82) \ + \ 3(0.4)}{0.4} \\\\F = 7.72 \ N

Learn more about net torque here: brainly.com/question/15262027

7 0
2 years ago
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