An 18-mm-wide diffraction grating has rulings of 710 lines per millimeter. monochromatic light of wavelength 506 nm wavelength i
1 answer:
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Answer:
Explanation:
We can use the equation of speed in terms of distance. We know that the speed of light is constant value so we will have:
Now we know that
I hope it helps you!
Answer:
The distance that separates the two particles is 7.42 cm.
Explanation:
Given;
the mass of each particle, m = 3 mg = 3 x 10⁻⁶ kg
the magnitude of charge of each particle, q = 6.0 nC
speed of each particle, v = 5.0 m/s
a = v/t
where;
a is the acceleration of the two particles
v is the final velocity
t is time
v = u + gt
5 = 0 + 9.8t
5 = 9.8t
t = 5/9.8
t = 0.51 s
a = v/t
a = 5/0.51 = 9.8 m/s²
Total force on the two particles = (2m)a = (2* 3 x 10⁻⁶)9.8
F = 5.88 x 10⁻⁵ N
Substitute in the value of F in the above equation and calculate r
where;
k is coulomb's constant = 8.99 x 10⁹ Nm²/c²
r is the distance of separation between the two particles
Therefore, the distance that separates the two particles at the instant when each has a speed of 5.0 m/s, is 7.42 cm.
Remember that sound intensity decreases in inverse proportion to the distance squared. So, to solve this we are going to use the inverse square formula: 
where
is the intensity at distance 2
is the intensity at distance 1
is distance 2
is distance 1
We can infer for our problem that
, 
, and 
. Lets replace those values in our formula to find :
dB
We can conclude that the intensity of the sound when is <span>3 m from the source is 30 dB.</span>
where
We can infer for our problem that
We can conclude that the intensity of the sound when is <span>3 m from the source is 30 dB.</span>