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mr_godi [17]
4 years ago
8

An 18-mm-wide diffraction grating has rulings of 710 lines per millimeter. monochromatic light of wavelength 506 nm wavelength i

s incident normally on the grating. what is the largest angle from the centerline at which an intensity maximum is formed?
Physics
1 answer:
aliina [53]4 years ago
7 0
W= 18*10^-3m 
N= 18*710 ( because you have 710 slits per mm ) = 12780 
lambda = 506*10^-9 

The first step is to workout d. 
d = w/N 
d =18*10^-3m/12780 
d =1.41*10^-6m 

The second step is to work out the maximum number of m. 
Since sin (theta) = less than 1, then m*lambda/d = less then 1,
therefore m= less than d/lambda 
( I know thats confusing but trust me ) 
so m is less than 1.41*10^-6m/506*10^-9 
= 2.7 
Therefore use m = 2 

Lastly put it all into the formula
dsin (theta) = m*lambda so:
theta = sin^-1(m*lambda/d) 
theta = sin^-1(2*506*10^-9/1.41*10^-6m) 
theta = 45.95 degrees or 46 degrees
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