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mr_godi [17]
4 years ago
8

An 18-mm-wide diffraction grating has rulings of 710 lines per millimeter. monochromatic light of wavelength 506 nm wavelength i

s incident normally on the grating. what is the largest angle from the centerline at which an intensity maximum is formed?
Physics
1 answer:
aliina [53]4 years ago
7 0
W= 18*10^-3m 
N= 18*710 ( because you have 710 slits per mm ) = 12780 
lambda = 506*10^-9 

The first step is to workout d. 
d = w/N 
d =18*10^-3m/12780 
d =1.41*10^-6m 

The second step is to work out the maximum number of m. 
Since sin (theta) = less than 1, then m*lambda/d = less then 1,
therefore m= less than d/lambda 
( I know thats confusing but trust me ) 
so m is less than 1.41*10^-6m/506*10^-9 
= 2.7 
Therefore use m = 2 

Lastly put it all into the formula
dsin (theta) = m*lambda so:
theta = sin^-1(m*lambda/d) 
theta = sin^-1(2*506*10^-9/1.41*10^-6m) 
theta = 45.95 degrees or 46 degrees
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In fact, the first rock is moving upward with velocity +4.5 m/s, while the second rock is moving downward with velocity -6.2 m/s, with respect to a fixed reference frame. In the reference frame of the first rock, instead, the second rock is moving with velocity equal to its velocity in the fixed frame minus the velocity of the reference frame of the first rock:
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