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NeX [460]
4 years ago
12

A car which is traveling at a velocity of 15 m/s undergoes an acceleration of 6.5 m/s2 over a distance of 340 m. How fast is it

going after that acceleration? (68.15 m/s)
Physics
1 answer:
Svetach [21]4 years ago
5 0

<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>

where <em>u</em> = initial velocity, <em>v</em> = final velocity, <em>a</em> = acceleration, and ∆<em>x</em> = distance traveled.

So

<em>v</em>² - (15 m/s)² = 2 (6.5 m/s²) (340 m)

<em>v</em>² = 4645 m²/s²

<em>v</em> ≈ 68.15 m/s

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