Answer:
Wind turbines are a source of clean renewable energy, but some people who live nearby describe the shadow flicker, the audible sounds and the subaudible sound pressure levels as "annoying." They claim this nuisance negatively impacts their quality of life
Answer:
22785 square inches
Explanation:
- As the mass of the tube is 30kg, therefore it is exerting a force of 30g N(30g = 30 × 9.8 = 294)
- So the force is 294 N.
- Pressure is 20 N/m², as given.
- As we know Pressure is equal to the force exerted per unit area (P=F/A).
A = 294 ÷ 20 = 14.7 m²
- As 1 m² = 1550 square inches. Therefore, 14.7 m² = 14.7 × 1550 square inches = 22785 square inches
If you want to know something more about pressure, force, and area, you can refer to this link:
https://brainly.in/question/1440079
Answer:
Explanation:
The relation between electric field and potential difference is as follows
E = - dV / dr
That means if dV is positive , E is negative . In other words , if potential increases , E is negative or in opposite direction in which potential increases .
Here the electric potential increases uniformly from east to west , that means electric field is from west to east . Since potential is uniformly increasing that means
dV / dr = constant
E = constant
Electric field is constant .
So the option which is correct is
" points east and does not vary with position " .
Answer:
Resultant amplitude is 0.53 m.
Explanation:
Amplitude is defined as the maximum displacement of wave particles from their respective mean positions.
The resulting amplitude of any two waves is given by the relation :
A = 
Here, A is resultant amplitude, A₁ and A₂ are the amplitudes of two waves respectively and x is the difference in phase angle of the two waves.
According to the problem, A₁ is 0.4 m , A₂ is 0.23 m and x is zero. So, the above equation becomes,
A = 
A = 
A = 0.63 m
Answer:

Given:
Initial speed (u) = 0 km/hr = 0 m/s
Final speed (v) = 36 km/hr
Time taken (t) = 10 sec
To Find:
Acceleration (a) of the train
Explanation:

So,
Final speed (v) = 10 m/s

Acceleration of train = 1 m/s²