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Helen [10]
4 years ago
6

When an object is moved from rest at point A to rest at point B in a gravitational field, the net work done by the field depends

on the mass of the object and
1. the nature of the external force moving the object from A to B.

2. the velocity of the object as it moves between A and B.

3. both the positions of A and B and the path taken between them.

4. the path taken between A and B only.

5. the positions of A and B only.
Physics
1 answer:
9966 [12]4 years ago
4 0

Answer:5. The positions of A and B only.

Explanation: Gravitational force or pull is the pull on all objects by the Earth Magnetic forces,it tends to attract all objects to itself. Gravitational field is a field induced by an object with mass, which will interact with other massive objects by applying a force on it . Gravitational field does not depend on the paths of motion of any object,its velocity, the nature of the forces around the object,the Gravitational force is known to be a conservative force,which tries to conserve its force.

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People living near wind farms sometimes object to them because of visual pollution and what other
ddd [48]

Answer:

Wind turbines are a source of clean renewable energy, but some people who live nearby describe the shadow flicker, the audible sounds and the subaudible sound pressure levels as "annoying." They claim this nuisance negatively impacts their quality of life

4 0
3 years ago
8. A round tube weighs 30 kg. If the tube is stood on end, it pushes down on the floor with a pressure of 20 N/m². How many squa
Rudik [331]

Answer:

22785 square inches

Explanation:

  • As the mass of the tube is 30kg, therefore it is exerting a force of 30g N(30g = 30 × 9.8 = 294)
  • So the force is 294 N.
  • Pressure is 20 N/m², as given.
  • As we know Pressure is equal to the force exerted per unit area (P=F/A).
  • Therefore, A=F/P

        A = 294 ÷ 20 = 14.7 m²

  • As 1 m² = 1550 square inches. Therefore, 14.7 m² = 14.7 × 1550 square inches = 22785 square inches

If you want to know something more about pressure, force, and area, you can refer to this link:

https://brainly.in/question/1440079

4 0
2 years ago
In a certain region of space the electric potential increases uniformly from east to west and does not vary in any other directi
Ne4ueva [31]

Answer:

Explanation:

The relation between electric field and potential difference is as follows

E = - dV / dr

That means if dV is positive , E is negative . In other words , if potential increases , E is negative or in opposite direction in which potential increases .

Here the electric potential increases uniformly from east to west , that means electric field is from west to east . Since potential is uniformly increasing that means

dV / dr = constant

E = constant

Electric field is constant .

So the option which is correct is

" points east and does not vary with position " .

3 0
3 years ago
A wave of amplitude 0.4 m interferes with a second wave of amplitude 0.23 m traveling in the same direction. What is the largest
jek_recluse [69]

Answer:

Resultant amplitude is 0.53 m.

Explanation:

Amplitude is defined as the maximum displacement of wave particles from their respective mean positions.

The resulting amplitude of any two waves is given by the relation :

A = \sqrt{A_{1} ^{2} + A_{2} ^{2} + 2A_{1}A_{2}\cos x   }

Here, A is resultant amplitude, A₁ and A₂ are the amplitudes of two waves respectively and x is the difference in phase angle of the two waves.

According to the problem, A₁ is 0.4 m , A₂ is 0.23 m and x is zero. So, the above equation becomes,

A = \sqrt{0.4^{2} + 0.23^{2} + 2\times 0.4\times 0.23\times cos 0   }

A = \sqrt{0.16 + 0.053 + 0.184   }

A = 0.63 m

4 0
3 years ago
a train starting from rest moving with uniform acceleration attains a speed of 36 km/hr in 10 seconds. Find its acceleration​
Savatey [412]

Answer:

\boxed{\sf Acceleration \ of \ train = 1 \ m/s^{2}}

Given:

Initial speed (u) = 0 km/hr = 0 m/s

Final speed (v) = 36 km/hr

Time taken (t) = 10 sec

To Find:

Acceleration (a) of the train

Explanation:

\sf 1 \ km/hr = \frac{5}{18} \ m/s \\ \therefore \\ \sf 36 \ km/hr = 36 \times \frac{5}{18} \ m/s \\  \\  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = 2 \times  \cancel{18} \times  \frac{5}{ \cancel{18}}  \ m/s \\  \\  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \: = 2 \times 5 \ m/s \\  \\  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 10  \ m/s

So,

Final speed (v) = 10 m/s

\sf From \ equation \ of \ motion: \\ \sf \implies \bold{v = u + at} \\ \\ \sf Substituting \ value \ of \ v, \ u \ and \ t: \\ \sf \implies 10 = 0 + a(10) \\ \sf \implies 10 = a(10) \\ \sf \implies a \times 10 = 10 \\ \\ \sf Dividing \ both \ sides \ by \ 10: \\ \sf \implies \frac{a \times 10}{\boxed{\sf 10}} = \frac{10}{\boxed{\sf 10}} \\ \\ \sf \frac{\cancel{10}}{\cancel{10}} = 1: \\ \sf \implies a = 1 \:  m/s^2

Acceleration of train = 1 m/s²

8 0
3 years ago
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