Question

suppose that glucose concentration in a red blood cell is 0.5mm and the concentration outside of the cell is 5 mm calculate the free energy change

Answer 1

Answer:

Change in free energy (ΔG) = 1.43 kcal/mol

Explanation:

Free energy is the energy released by a diffusing molecule moving up or down a concentration gradient, across a membrane.

The formula for free energy change import into a membrane is given by the formula :

$\triangle G = \triangle G^0 + R \times T \times In\frac{[X]_{inside}}{[X]_{outsdie}}$

where:

$\triangle G = change\ in\ free\ energy\\\triangle G^0 = initial\ charge\ on molecule = 0 (Glucose\ molecule\ is\ uncharged)\\R = gas\ constant\ = 2 (cal/mol.K)\\T =Absolute\ temperature= \ ^oK = ^oC + 273 = 37 + 273 = 310\ ^oK (Note: body\ temperature\ = 37^oC)\\In = Natural\ logarithm$

$[X]_{inside} = concentration\ of\ glucose\ inside\ the\ cell = 0.5mM\\ {[X]}_{outside} = concentration\ of\ glucose\ outside\ the\ cell = 5mM$

$\triangle G = 0 + (2) \times (310) \times In\frac{[0.5]}{[5]} \\\triangle G = 620 \times In (0.1)\\\triangle G = 620 \times (-2.3)\\\triangle G = -1426\ cal/mol\\\triangle G = 1.43\ kcal/mol$