Answer:
10% of progeny would have wild type phenotype
Explanation:
True breeding fly with wild type wings and small eyes: De/De
True breeding fly with downward wings and wild type eyes: dE/dE
Cross between them : De/De X dE/dE = De/dE ( F1 )
Recombination frequency = 20%
Next cross, De/dE X de/de =
De/de = parental = 40%
dE/de = parental = 40%
DE/de = recombinant = 10%
de/de = recombinant = 10%
The third genotype i.e. one of the recombinant genotypes will have the wild type makeup ( DE/de ) hence 10% of flies would have wild type phenotype.
Answer:
In a eukaryotic cell
Explanation:
"<em>In a eukaryotic cell, transcription occurs in the nucleus, and translation occurs in the cytoplasm.</em>"
Credit goes to www.phschool.com
Answer:
b. active transport
Explanation:
Active transport -
It is the movement of the molecules across the membrane via a region of lower concentration towards the region of higher concentration , and in some cases , the flow is independent of the concentration .Its is known as active transport .
This process needs some amount of energy in the form of cellular energy .
Hence , the correct term for the given statement is active transport .
Complete question:
You will find the complete question and answer in the attached files
Answer:
a) LL- <em> Long nose</em>
b) yy- <em>Blue body</em>
(c) Ss- <em>Squarepants body</em>
(d) RR- <em>Round eyes</em>
(e) Rr- <em>Round eyes</em>
(f) ll- <em>Stubby nose</em>
(g) ss- <em>Roundpants body</em>
(h) Yy- <em>Yellow body</em>
Explanation:
You will find the complete answer and explanation in the attached files due to technical problems.
