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Tom [10]
2 years ago
9

Find the number of possible positive real zeros of 2x^4+14x^3-35x^2

Mathematics
1 answer:
Kazeer [188]2 years ago
7 0
Possible zeros: Factors of P/Factors of Q, where P is the constant and Q is the leading coefficient.

P = 35: 1, 5, 7, 35
Q = 2: 1, 2
+1, -1, +1/2, -1/2, +5, -5, +5/2, -5/2, +7, -7, +7/2, -7/2, +35, -35, + 35/2, -35/2
16 total
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Here are the percents of the popular
kvv77 [185]

Answer: 57.4

Step-by-step explanation:

First order the numbers from the smallest to the largest:

49.6, 55.1, 57.4, 49.7, 61.1, 43.4,  60.7, 50.1, 50.7, 58.8, 53.9, 43.2,  49.2, 47.9, 51.2

to:

43.2, 43.4, 47.9, 49.2, 49.6, 49.7, 50.1, 50.7, 51.2, 53.9, 55.1, 57.4, 58.8, 60.7, 61.1.

The position of third quartile is:

= (N + 1) * 3/4

= (15 + 1) * 3/4

= 12th position

That number is:

= 57.4

8 0
2 years ago
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zmey [24]

Answer:

4

Step-by-step explanation:

4 : 1, 2,4

12 :1, 2, 3, 4, 6, 12

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3 years ago
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lyudmila [28]
Since sale is 40% so the price is 60%

61*(60%) = 36.6

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so the price after tax is: 36.6 * (1 +5%) = $38.43
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Solve for x. <br><br> a²x+(a-8)=(a+8)x
Sergio [31]
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6 0
2 years ago
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