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mojhsa [17]
3 years ago
8

F(x)= 2x^3-10x^2+12x-12 Find critical points

Mathematics
1 answer:
elena-s [515]3 years ago
3 0

Answer:

Find where the first derivative is equal to 0

. Enter these values into the original function and simplify to find the critical points.

<h2>(5+√7/3,−284+28√7/27),(5−√7/3,−284−28√7/27)</h2>

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Meg purchased a stereo system at a local store. It cost $675. She paid for it in six equal installments of $139 each. How much i
yawa3891 [41]

Answer:

159

Step-by-step explanation:

She paid 6 payments of 139

6*139 = 834

The cost was 675

834-675 =159

The interest was 159

8 0
3 years ago
Find the radius of a circle with an area of 380 square inches. Round your answer to the nearest hundredth
KonstantinChe [14]

Answer:

Step-by-step explanation:

Area of a circle is defined as

A = πr²

Where

A is the area of the circle

r Is the radius of the circle

π is a constant = 3.142

Then,

Given that the area is 380 in²

So,

A = πr²

380 = 3.142 × r²

Divide both side by 3.142

380 / 3.142 = 3.142 × r² / 3.142

111.372 = r²

Take square root of both sides

√111.372 = √r²

10.5533 = r

r = 10.5533 in

Nearest hundredth means to 2d.p

Therefore

r = 10.55 inches

7 0
2 years ago
Read 2 more answers
Write the fraction<br> in simplest form.<br> 42/49
lozanna [386]

Answer:

6/7 is the ans

42 & 49 is divided by 7

4 0
3 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
Shade the model to 0.5 x 0.3
stellarik [79]
What model? also it would be 1/2 and 1/3
6 0
3 years ago
Read 2 more answers
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