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V125BC [204]
3 years ago
14

What is the product? Enter your answer as a fraction, in simplified form, in the box. −1/4⋅(−6/11)

Mathematics
1 answer:
ivann1987 [24]3 years ago
4 0

Answer:

3/22

Step-by-step explanation:

-1/4 . (-6/11)

  • You have to multiply the signs: As both are negative, the result will be positive.
  • You have to multiply the numbers in the top part (numerators) and the numbers in the bottom part (denominators)

1 . 6 / 4 . 11 = 6/44

  • Finally, you must simplify the answer by dividing both numbers among the same divisor, in this case the number is 2

6÷2 / 44÷2 = 3/22

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What is the substitution of -6x-8y=-20 and x+6y=-6
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Substitution doesn't work for this, but elimination does.

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-6x-8y=-20 + 6x+36y=-36

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divide by 28 on both sides.

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A poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ag
Katyanochek1 [597]

Answer:

At 5% significance level, it is statistically evident that    there is nodifference in the proportion of college students who consider themselves overweight between the two poll                                  

Step-by-step explanation:

Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.

Let five years ago be group I X and as of now be group II Y

H_0: p_x =p_y\\H_a: p_x \neq p_y

(Two tailed test at 5% level of significance)

                Group I            Group II              combined p

n                  270                 300                         570

favor            120                  140                          260

p                   0.4444            0.4667                   0.4561

Std error   for differene = \sqrt{\frac{0.4561(1-0.4561)}{570} } \\=0.0209

p difference = -0.0223    

Z statistic = p diff/std error =       -1.066

p value =0.2864

Since p value >0.05, we accept null hypothesis.

        At 5% significance level, it is statistically evident that    there is nodifference in the proportion of college students who consider themselves overweight between the two poll                                  

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