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Katen [24]
3 years ago
11

What is the equation of the graphed line in point-slope form?

Mathematics
1 answer:
Tomtit [17]3 years ago
8 0
ANSWER

y - 1 = \frac{2}{3} (x - 3)

EXPLANATION

To find the equation in point-slope form, use the formula,

y-y_1=m(x-x_1)

The m
is the slope of the line.

We can read from the graph that, the straight line passes through, the points
(-3,-3) \: and \: (3,1)

We can use these two points to find the slope of the line.

The slope can found using the formula,

m=\frac{y_2-y_1}{x_2-x_1}

This means that,

m = \frac{1 - - 3}{3 - - 3}

m = \frac{1 + 3}{3 + 3}

m = \frac{4}{6}

m = \frac{2}{3}

We now use one of the points, say
(3,1)
with the slope to find the equation of the line.

y - 1 = \frac{2}{3} (x - 3)
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sashaice [31]

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Step-by-step explanation:

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Please help me <br> Show your work <br> 10 points
Svet_ta [14]
<h2>Answer</h2>

After the dilation \frac{5}{3} around the center of dilation (2, -2), our triangle will have coordinates:

R'=(2,3)

S'=(2,-2)

T'=(-3,-2)

<h2>Explanation</h2>

First, we are going to translate the center of dilation to the origin. Since the center of dilation is (2, -2) we need to move two units to the left (-2) and two units up (2) to get to the origin. Therefore, our first partial rule will be:

(x,y)→(x-2, y+2)

Next, we are going to perform our dilation, so we are going to multiply our resulting point by the dilation factor \frac{5}{3}. Therefore our second partial rule will be:

(x,y)→\frac{5}{3} (x-2,y+2)

(x,y)→(\frac{5}{3} x-\frac{10}{3} ,\frac{5}{3} y+\frac{10}{3} )

Now, the only thing left to create our actual rule is going back from the origin to the original center of dilation, so we need to move two units to the right (2) and two units down (-2)

(x,y)→(\frac{5}{3} x-\frac{10}{3}+2,\frac{5}{3} y+\frac{10}{3}-2)

(x,y)→(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

Now that we have our rule, we just need to apply it to each point of our triangle to perform the required dilation:

R=(2,1)

R'=(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

R'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(1)+ \frac{4}{3})

R'=(\frac{10}{3} -\frac{4}{3} ,\frac{5}{3}+ \frac{4}{3})

R'=(2,3)

S=(2,-2)

S'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

S'=(\frac{10}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

S'=(2,-2)

T=(-1,-2)

T'=(\frac{5}{3} (-1)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

T'=(-\frac{5}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

T'=(-3,-2)

Now we can finally draw our triangle:

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Aloiza [94]

Answer:

3/4.

Step-by-step explanation:

There are 3 non leap years  in every 4 year period so it s 3/4.

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Thank you everyone for helping me this year to get good grades I am giving points.​
Dmitriy789 [7]
Yayyyy I’m so happy you got good grades
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