What is the whole nunnery 13,260,000in expanded form?
1 answer:
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Answer:
The solution is given below;
Step-by-step explanation:
The computation is shown below:
There is six equal sections are numbered i.e. 2, 2, 3, 4, 5, and 6.
And, Number of Outcome of 2 on the Spinner is 2
Also, total Number of Sections is 6
As the winning spin is a 2
So, The theoretical probability of winning
= 2 ÷6 × 100
= 33.33%
Now
There is a total no of trials be 120
And, the number of outcome of 2 be 30
So, the experimental probability is 30 ÷ 120 = 1 ÷ 4 × 100 = 25%
As 33.3%>25%, this represent that the theoretical probability of winning would be greater.
Answer:
9
Step-by-step explanation:
Arrange data set
19, 4, 17, 3, 6, 5,5, 3, 11, 12, 3, 7, 15, 8, 8, 10,5, 3, 12, 41, 36
in ascending order
3, 3, 3, 3, <u>4, 5,</u> 5, 5, 6, 7, 8, 8, 10, 11, 12, <u>12, 15,</u> 17, 19, 36, 41
The median is
Thus, the interquartile range is
Bill's speed is constant after 5 seconds and 45 meters into the race.
Correct responses:
a. Bill's maximum speed is 8 m/s
b. 24 meters
c. 57 meters
<h3>Methods used to calculate speed and distance traveled</h3>Given parameters are;
The distance of the race = 100 meter
Distance at which Bill reaches maximum speed = 45 meters
Speed Bill maintains after 5 seconds = The maximum speed
Time at which Bill is 85 meters from the starting line = 10 seconds after start
a. Required;
Bill's maximum speed in meters.
Solution:
Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m
Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s
Therefore;
b. i. Required:
The distance Bill will run for 3 seconds at the maximum speed;
Solution:
Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>
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The distance traveled at maximum speed in 3 seconds is therefore;
Distance = 8 m/s × 3 s = 24 m
The distance Bill travels in 3 seconds at the maximum speed is 24 meters.
ii) The distance Bill travels at 8 seconds after start, is given as follows;
Distance traveled in the first 5 seconds = 45 meters
Distance traveled in the next 3 seconds = 24 meters
Therefore;
- Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>
c. Bill's distance 6.5 seconds after the start of the race is given as follows;
Distance traveled in the first 5 seconds = 45 meters
Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters
- Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>
Learn more about distance, speed, time, relationship here:
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