Graph the six terms of a finite sequence where a1= -10 and d=3
1 answer:
I'm assuming your problem is about an arithmetic sequence, with first term equal to -10 and a common difference of 3 (meaning add 3 to a term to get the next term.
The first six terms are -10, -7, -4, -1, 2, 5.
To make a graph, plot points (1, -10), (2, -7), (3, -4), (4, -1), (5, 2), and (6, 5). See the attached picture. The points go steadily uphill, in a straight line. Any arithmetic sequence with a positive common difference will do just that!
Hope this helps!
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Assuming you mean this as your problem I hope I can assist you.
So just apply the exponent rule to start, which is (a/b)^c = a^c/b^c
This translates to....
Now apply the exponent rule (a^b)^c = a^bc
Which translates to 3^2 * 4 which is refined to 3^8
So now we have....
Just apply the exponent rule (a^b)^c
So we get 2^5 * 4 which refines to 2^20
Therefore our final answer is 2^20/3^8
So just apply the exponent rule to start, which is (a/b)^c = a^c/b^c
This translates to....
Now apply the exponent rule (a^b)^c = a^bc
Which translates to 3^2 * 4 which is refined to 3^8
So now we have....
Just apply the exponent rule (a^b)^c
So we get 2^5 * 4 which refines to 2^20
Therefore our final answer is 2^20/3^8