Graph the six terms of a finite sequence where a1= -10 and d=3
1 answer:
I'm assuming your problem is about an arithmetic sequence, with first term equal to -10 and a common difference of 3 (meaning add 3 to a term to get the next term.
The first six terms are -10, -7, -4, -1, 2, 5.
To make a graph, plot points (1, -10), (2, -7), (3, -4), (4, -1), (5, 2), and (6, 5). See the attached picture. The points go steadily uphill, in a straight line. Any arithmetic sequence with a positive common difference will do just that!
Hope this helps!
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Answer:
So the solution set of the equations are {(-1,4)}
or
the solution is x = -1 and y = 4
Step-by-step explanation:
Equations given to us are
y = -3x + 1 ..................(i)
2x + 5y = 18 .................(ii)
To find the value of x and y or the solution set of the system of equations
Now in first equation we see that
y = -3x + 1
Putting this value in equation (ii)
which is
2x + 5y = 18
Putting value of y from (i) in it
2x + 5(-3x + 1) = 18
Opening the bracket and multiplying inside
2x -15x + 5 = 18
-13 x + 5 = 18
Subtracting 5 from both sides of the equation
-13x + 5 - 5 = 18 -5
-13x = 13
Dividing both sides by -13
Cutting out the same values gives us
x = -1
For value of y
putting value of x in equation (i)
which is
y = -3x + 1
Putting the value
y = -3(-1)+1
y=3+1
y=4
So the solution set of the equations are {(-1,4)}
or
the solution is x = -1 and y = 4