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Strike441 [17]
3 years ago
9

An exterior angle of a regular convex polygon is 40°. What is the number of sides of the polygon?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0

The Exterior Angles of a Polygon add up to 360°, so there must be 9 sides, since 9*40=360.


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george completed 3/5th of work in 9 days with the help of paul he completes remaining work in 4 days.In how many days paul alone
IRINA_888 [86]
If George completed 3/5 of work in 9 days, it means that he needs 3 days to finish 1/5th of the work.

The remaining part is 2/5 because 1-3/5=2/5. 2/5 is also 6/15

From this, how much did George do? in the first 3 days he did 1/5th and then one more day was left, during which he did 1/5/3=1/15th.

So he did in total 1/15+1/5=1/15+3/15=4/15.
this means that Paul did the rest of 6/15, so Paul did 6/15-4/15=2/15.

So we know that he does 2/15 in 4 days, which means that every two days he can do 1/15 of the work

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3 years ago
HELP ASAP I WILL GIVE 20 POINTS HELPPPPPPPPPPPP
Nikolay [14]
52s + 30b because 52 x s + 30 x b = 52s + 30b
6 0
2 years ago
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Which of the following is a factor of 2xy + 8y − 8x − 32?
muminat
You could start by eliminating wrong answer(s):

(a) 5 is definitely not a factor of the given <span>2xy + 8y − 8x − 32,

(d) x^2 - 4x + 16 (not x2 - 4x + 16) is not a factor (it has no y terms)

On the other hand:

(b) 2 definitely divides evenly into </span>2xy + 8y − 8x − 32:  2(<span>xy + 4y − 4x − 16)

(c) x + 4 divides evenly into both xy + 4y and -(4x + 16):
                                           We get 2(x +4) [y - 4]</span>
4 0
3 years ago
Find the nth taylor polynomial for the function, centered at c. f(x) = ln(x), n = 4, c = 5
masha68 [24]

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Given:

f(x) = ln(x)

n = 4

c = 3

nth Taylor polynomial for the function, centered at c

The Taylor series for f(x) = ln x centered at 5 is:

P_{n}(x)=f(c)+\frac{f^{'} (c)}{1!}(x-c)+  \frac{f^{''} (c)}{2!}(x-c)^{2} +\frac{f^{'''} (c)}{3!}(x-c)^{3}+.....+\frac{f^{n} (c)}{n!}(x-c)^{n}

Since, c = 5 so,

P_{4}(x)=f(5)+\frac{f^{'} (5)}{1!}(x-5)+  \frac{f^{''} (5)}{2!}(x-5)^{2} +\frac{f^{'''} (5)}{3!}(x-5)^{3}+.....+\frac{f^{n} (5)}{n!}(x-5)^{n}

Now

f(5) = ln 5

f'(x) = 1/x ⇒ f'(5) = 1/5

f''(x) = -1/x² ⇒ f''(5) = -1/5² = -1/25

f'''(x) = 2/x³  ⇒ f'''(5) = 2/5³ = 2/125

f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625

So Taylor polynomial for n = 4 is:

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Hence,

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Find out more information about nth taylor polynomial here

brainly.com/question/28196765

#SPJ4

3 0
1 year ago
Determine if the ratio or rates are equivalent: 24 points scored in 4 games; 48 points scored in 10 games ASAP ANSWER IT I NEED
koban [17]

Answer:

Step-by-step explanation:

Yes: 24 points/4 games = 6 points per game while 48 points/10 games = 24 points in 5 games.

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3 years ago
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