Please help!! I’ll mark the correct answer as brainly

Mathematics

2 answers:

GenaCL600 [577]3 years ago

4 0

The answer is B. There can not be any alike "x" inputs.

liraira [26]3 years ago

3 0

In the point (x,y), x represents the domain of the function, and y represents the range of the function. A function is a part of a relation. In a relation, one domain can have multiple ranges. But in a function, one domain can not have multiple ranges. And in a function, multiple domains can have a range.

A function is a part of a relation. But a relation isn't always a function.
Function:
one domain only has a range, multiple domains can have one range

First option is not a function, it's a relation. Because one domain has multiple ranges ⇒ (0,3), (0,6)
Second option is a function! Because there's no multiple domains who have a range.
Third option is not a function, it's a relation. (1,4) and (1,6) is what makes it isn't a function.
Fourth option is not a function ⇒ (2,3), (2,6)

The answer is second option

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What IS 20 divided by 13 ?

goldenfox [79]

$Solution,\mathrm{Convert\:improper\:fractions\:to\:mixed\:numbers}:\quad \frac{20}{13}=1\frac{7}{13}$

$Steps:$

$\frac{20}{13}$

$\mathrm{Long\:Division}\:\frac{20}{13}:\quad 1\quad \mathrm{Remainder}\quad \:7$

$Convert\:to\:mixed\:number:\:Quotient\frac{Remainder}{Divisor},\\\frac{20}{13}=1\frac{7}{13}$

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3 years ago

Read 2 more answers

A report indicated that 37% of adults had received a bogus email intended to steal personal information. Suppose a random sample

fiasKO [112]

Answer:

5.05% probability that no more than 34% had received such an email.

Step-by-step explanation:

We use the binomial approximation to the normal to solve this problem.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .