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Vera_Pavlovna [14]
2 years ago
10

PLS HURRY FIRST ONE TO DO IT GETS BRAINLEIST Maria and her classmates are standing with other people in a line of 35 people wait

ing to buy tickets. Maria is last in this line of classmates and 20th from the front of the whole line. Maria's classmate leading the line of classmates is 23rd from the end of the whole line. How many classmates does Maria have?
Mathematics
1 answer:
solniwko [45]2 years ago
4 0

Answer:

7 classmates

Step-by-step explanation:

The last person in the line is in position 35.

The Maria's leading classmate is in the position 35-23+1 = 13.

So, Maria's classmates are from position 13 to 19 (not including herself), and their number is 19-12 = 7 persons.

ANSWER.  Maria has 7 classmates  (not including herself).

Hope this helps.

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Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩
NISA [10]

Answer:

\theta = 108.29

Step-by-step explanation:

Given

u =

v =

Required:

Calculate the angle between u and v

The angle \theta is calculated as thus:

cos\theta = \frac{u.v}{|u|.|v|}

For a vector

A =

A = a * b

cos\theta = \frac{u.v}{|u|.|v|} becomes

cos\theta = \frac{.}{|u|.|v|}

cos\theta = \frac{2*6+4*-7}{|u|.|v|}

cos\theta = \frac{12-28}{|u|.|v|}

cos\theta = \frac{-16}{|u|.|v|}

For a vector

A =

|A| = \sqrt{a^2 + b^2}

So;

|u| = \sqrt{2^2 + 6^2}

|u| = \sqrt{4 + 36}

|u| = \sqrt{40}

|v| = \sqrt{4^2+(-7)^2}

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|v| = \sqrt{65}

So:

cos\theta = \frac{-16}{|u|.|v|}

cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}

cos\theta = \frac{-16}{\sqrt{2600}}

cos\theta = \frac{-16}{\sqrt{100*26}}

cos\theta = \frac{-16}{10\sqrt{26}}

cos\theta = \frac{-8}{5\sqrt{26}}

Take arccos of both sides

\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})

\theta = cos^{-1}(\frac{-8}{5 * 5.0990})

\theta = cos^{-1}(\frac{-8}{25.495})

\theta = cos^{-1}(-0.31378701706)

\theta = 108.288386087

<em></em>\theta = 108.29<em> (approximated)</em>

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2 years ago
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