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2 years ago

Reflect (1,‐4) across the x‐axis what is the reflected ordered pair?

Mathematics

2 answers:

lidiya [134]2 years ago

8 0

Answer: (1,4)

Step-by-step explanation:

The rule for reflecting over the X axis is to negate the value of the y-coordinate of each point, but leave the x-value the same. For example, when point P with coordinates (1,-4) is reflecting across the X axis and mapped onto point P', the coordinates of P' are (1,4)

alexandr1967 [171]2 years ago

4 0

Answer:

(1,4)

Step-by-step explanation:

(1,-4) is over 1 and down negative 4 so reflected over the x-axis(the horizontal one) it would be four up so the answer is (1,4)

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Distribute (2m-5m)(-5)

Reika [66]

First Method (Distributive Property)

(2m - 5m) (-5)

Rearrange the equation to make it easier.

(-5) (2m - 5m)

In distributive property, it's all about multiplying. The -5 goes to the 2m and the 5m. Like this: (-5 • 2m) - (-5 • 5m).

-10m + 25m

15m

Second Method

(2m - 5m) (-5)

Since 2m and 5m have the same variable, we can subtract them.

(-3m) (-5)

Multiply.

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3 years ago

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irakobra [83]

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3 years ago

A set of data items is normally distributed with a mean of 240 and a standard deviation of 32. Convert 272 to a? z-score

dem82 [27]

Answer:

z-score = 1

Step-by-step explanation:

Given

Mean= μ=240

SD= σ=32

In order to find the z-score of a value, the mean is subtracted from the value and then divided by standard deviation.

The formula for z-score is:

z-score=(x-μ)/σ

Here x is the value whose z-score is to be found.

In the given question, x = 272

So,

z-score=(272-240)/32

=32/32

So , the z-score for 272 is 1..

7 0

3 years ago

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in slope-intercept formula, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of k and m.

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

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2 years ago

20x^2-12x-8 a. (10x+2) (2x+5) b.(5x+2) (4x-4) c. (5x-2) (4x+4) d. (10x-2) (2x-5)

almond37 [142]

Answer:

Step-by-step explanation:

20x^2 - 12x - 8

4 ( 5x^2 - 3x - 2 )

5 * - 2 = - 10

Factors of - 10

1 , - 10

10, - 1

2, - 5

5, - 2

5x^2 - 5x + 2x - 2

5x (x - 1) 2 (x - 1)

4 (x - 1) (5x + 2)

(4x - 4) (5x + 2)

7 0

2 years ago

Reflect (1,‐4) across the x‐axis what is the reflected ordered pair?​

Reflect (1,‐4) across the x‐axis what is the reflected ordered pair?