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3241004551 [841]

4 years ago

8

When forces are balanced, what affect does that have on the motion of an object?

2 answers:

salantis [7]4 years ago

7 0

Balanced forces cause no change in motion, even if the object is moving.

ElenaW [278]4 years ago

5 0

According to Newton’s 1st law, all objects remain stable unless acted upon by an unbalanced force, so this means that since the forces are balanced, the motion would remain at rest. If there was a greater force on one side of the object, then it would be pushed to the other side (ex. Pushing a heavy box from the right, makes it go left). I hope that helps...

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a coin is dropped from the top of a tall building. determine the coin's (a) velocity and (b) displacement after 1.5 sec.

Lilit [14]

1) v = gt = 10*1.5 = 15 m/s
2) r = gt^2 /2 = 10*(1.5)^2 / 2 = 11.25 meters

8 0

3 years ago

Q7:<br> A 4 kg toy is lifted off the ground and falls at 3 m/s. What is the toy's energy?

alexandr1967 [171]

Answer:

The toy's energy is 18 J.

Explanation:

We have, a 4 kg toy is lifted off the ground and falls at 3 m/s. It is required to find toy's energy.

The toy will have kinetic energy due to its motion. The energy is given by :

$E=\dfrac{1}{2}mv^2\\\\E=\dfrac{1}{2}\times 4\times 3^2\\\\E=18\ J$

So, the toy's energy is 18 J.

7 0

3 years ago

Polar molecules have ionic bonds.<br> True<br> False

Nadusha1986 [10]

Polar molecules do have ionic bonds

6 0

3 years ago

g If you keep the launch angle fixed, but double the initial launch speed, what happens to the range?

kiruha [24]

Answer:

Range will become 4 times of initial range

Explanation:

Let the velocity of projection is u

And angle at which projectile is projected is $\Theta$

And acceleration due to gravity is $g\ m/sec^2$

So range of projectile is equal to $R=\frac{u^2sin2\Theta }{g}$ ........eqn 1

Now in second case it is given that velocity of launching is doubled

So new velocity $u_{new}=2u$

So new range will be equal to $R_{new}=\frac{(2u)^2sin2\Theta }{g}=\frac{4u^2sin2\Theta }{g}$ .....eqn 2

Now dividing eqn 2 by eqn 1

$\frac{R_{new}}{R}=\frac{4u^2sin2\Theta }{g}\times \frac{g}{u^2sin2\Theta }$

$R_{new}=4R$

So if we double the initial launch speed then range will become 4 times

4 0

4 years ago

A pilgrim uses a block and tackle to lift a 225 N crate a distance of 16.5 m. She pulls 33.0 m of rope with a force of 125 N. Wh

kenny6666 [7]

Answer:

Ideal mechanical advantage of the machine is 2

Explanation:

Ideal mechanical advantage of the machine is

$MA=\frac{op}{ip} \\$

here we have to consider the distance

$MA=\frac{33}{16.5} \\MA=2$

7 0

3 years ago