When a car turns a corner on a level road, which force provides the necessary centripetal acceleration?
1 answer:
Answer:
The frictional force between the tire made with the road
Explanation:
This car on level ground is moving away and turning to the left. The centripetal force causing the car to turn in a circular path is due to friction between the tires and the road. A minimum coefficient of friction is needed, or the car will move in a larger-radius curve and leave the roadway.
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Answer:
vₓ = 5.5 mile / h and = 2.5 mile/h
Explanation:
This is a problem of adding vectors, but since the canoe and the river are in the same direction, we can make an ordinary sum, write the equations for each situation
I rowed down the river. In this case the speed of the canoe and the river are in the same direction, consequently, they add up
(vₓ + ) = d / 1.5
I rowed up. In this case the canoe and the river have reversed directions
(vₓ- ) = d / 4
Feel us two equations with two unknowns,
Let's start by adding the equations
2vₓ = d / 1.5 + d / 4
2vₓ = 12 (4 + 1.5) / 4 1.5
vₓ = 11/2
vₓ = 5.5 mile / h
Let's substitute in the first of the two equations to find the speed of the river
(vₓ +) = d / 1.5
= d / 1.5 - vr
= 12 / 1.5 -5.5
= 8-5.5
= 2.5 mile / h
To calculate the kinetic coefficient of friction is closest to: 1. 0.23.
<u>Given the following data:</u>
- Horizontal force = 4.5 Newton
- Normal force = 20 Newton
- Speed = 3.0 m/s
To calculate the kinetic coefficient of friction:
Mathematically, the kinetic force is given by this formula;
<u>Where;</u>
represents the kinetic force.
is the normal force.
- μ represents the kinetic coefficient of friction.
Making μ the subject of formula, we have:
Substituting the given parameters into the formula, we have;
u = 0.225 ≈ 0.23
Read more on kinetic coefficient of friction here: brainly.com/question/13940648