We will apply the Newton's second Law so the we will be able to find the acceleration.
F (tot) = ma
a = F(tot) / m
a = 32.0 N / 65.0 kg = 0.492 m/s^2
Approximately 0.492 m/s^2 is her initial acceleration if she is initially stationary and wearing steel-bladed skates.
C is incorrect because the atomic number and symbol are the only ones displayed.
I think it could be A but it is most likely C
Hope it helps!!
In a constant acceleration of 3m per second, after 10 seconds,
3 x 10 = 30
B. 30m/s is your answer
hope this helps XD
Answer:
vb = 22.13 m/s
Explanation:
ma = 124 kg
mb = 13 kg
vi = 2.10 m/s
According to the property of conservation of momentum, and considering that, initially, both the astronaut and the bag moved together at 2.10 m/s:

The minimum final velocity of the bag, vb, the will keep the astronaut from drifting away forever occurs when va = 0:

The minimum final velocity of the bag is 22.13 m/s.