F(x) = x^2 - 6x + 4 {-3, 0, 5} (x, y) x is the domain, y is the range.
plug in the domain numbers into the equation to find the range.
y = x^2 - 6x + 4
y = -3^2 - 6(-3) + 4
y = 9 - (-18) + 4
y = 9 + 18 + 4
y = 31 (-3, 31)
y = x^2 - 6x + 4
y = 0^2 - 6(0) + 4
y = 0 - 0 + 4
y = 4 (0, 4)
y = x^2 - 6x + 4
y = 5^2 - 6(5) + 4
y = 25 - 30 + 4
y = -1 (5, -1)
c. {-1, 4, 31}
hope this helped, God bless!
Answer:
∠WVX = 35°
Step-by-step explanation:
Look at the rough draw.
As you can see,
VW ║ YZ
So ∠XWV is congruent to ∠XYZ through alternate interior angle.
We can solve ∠WVX by considering the two other angles, 88° and 57°.
Total angle of a triangle is 180°.
So,
? + 88 + 57 = 180
? + 145 = 180
? = 180 - 145
? = 35°
Answer:
I cannot answer all of this, so I will only answer what I can:
Q1: 13
Q3: 22.5
IQR: 13.5
IQR(1.5): 20.25
Q3 + IQR(1.5) = 43
Q1 - IQR(1.5) = -7.25
I don't know if my calculations are all right but I hope this helps! :)
Answer:
(2x-9)(2x+9)
Step-by-step explanation:
This is a difference of squares because it can be written as (2x)^2-9^2
The formula for factoring a difference of squares is a^2-b^2=(a-b)(a+b)
So replace a with 2x and b with 9 giving us
4x^2-81=(2x-9)(2x+9)
If the axis is x then you go to y so (6, 5)
