<span>
</span><span>http://www.squiglysplayhouse.com/BrainTeasers/bt.php?id=119
this should help</span>
2(3t - 1) - 5(t - 1)
2(3t) - 2(1) - 5(t) + 5(1)
6t - 2 - 5t + 5
6t - 5t - 2 + 5
t + 3
You cannot add row 2 to column 3 because they have different dimensions. You can do any of the other operations, but the only one that makes any sort of sense is ...
Multiply row 2 by -1 and add it to row 3
_____
It makes no sense to multiply a row by zero. That makes the entire row zero and makes the matrix useless for finding any sort of solution.
You can switch columns, but that doesn't get you any closer to a solution here.
If I were trying to find a solution, I might
switch rows 1 and 2
multiply the new row 1 by -3 and add it to the new row 2
multiply the new row 1 by 2 and add it to row 3
This sequence of operations will make the first column [1 0 0], reducing the problem to 2×2 from 3×3.
Answer:
3.2
Step-by-step explanation:
Given the coordinates
X(4, -3)
Y(2, 1.5)
A(3, 3)
Z(4,-1)
We are to find the distance from point A to XZ
First let us get the coordinate XZ
According to vector notation XZ = Z-X
XZ = (4,-1)-(4,-3)
XZ = [(4-4),-1-(-3)]
XZ = (0, 2)
Next is to find the distance from A(3, 3) to XZ(0,2) using the formula for calculating the distance between two points.
D = √(x2-x1)²+(y2-y1)²
x1 = 3, y1 = 3, x2 = 0, y2 = 2
D = √(0-3)²+(2-3)²
D = √9+1
D = √10
D = 3.16
Hence the distance from point A to XZ to nearest tenth is 3.2
