The length of a rectangle is 1 ft more than double the width, and the area of the rectangle is 45 ft2 . find the dimensions of t
he rectangle.
1 answer:
A = L * W
A = 45
L = 2W + 1
45 = W(2W + 1)
45 = 2W^2 + W
2W^2 + W - 45 = 0
(2W - 9)(W + 5) = 0
W + 5 = 0
W = -5...not this one because it is negative
2W - 9 = 0
2W = 9
W = 9/2
W = 4.5 <=== the width is 4.5 ft
L = 2W + 1
L = 2(4.5) + 1
L = 9 + 1
L = 10 <=== the length is 10 ft
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It would be B, hope i could help out.
Answer:
-4
Step-by-step explanation:
-4/3÷2/-6
⇒ -4/3×-6/2
⇒ -24/6
⇒ -4
C, A, B
A’s rate if change:
3
B’s rate of change:
(10 - 0) / (-2 - (-4)) = 10 / 2
5
C’s rate of change:
1
THE first option is correct
