A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
Answer:
Step-by-step explanation:
First let's find the radius of the quarter circle.
Now let's find the arc length of this quarter circle.
Now let's find the perimeter
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>
<em>brainliest</em><em> </em><em>appreciated</em>
<em>good</em><em> </em><em>luck</em><em>!</em><em> </em><em>have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>!</em>
Answer:
8x^2+3x
Step-by-step explanation:
What I read is 2x+8x^2-4x+5x
combining like terms means putting the terms that have the same variable part together
8x^2 is the only one that doesn't have any terms like it as far as the variable part
so 8x^2+2x-4x+5x
We just need to figure out 2-4+5 which is -2+5=3
So the answer is 8x^2+3x