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3 years ago

Long division 236 divided 4

Mathematics

2 answers:

madreJ [45]3 years ago

6 0

The answer would be 59 if you work our your division and do it correctly

vesna_86 [32]3 years ago

3 0

The corret answer is <u><em>59</em></u>

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Solve for r: C = 2 pi r. (1

katen-ka-za [31]

Answer:

C/2pi = r

Step-by-step explanation:

C = 2 pi r

divide with 2 pi on both sides to solve for r

C/2pi = r

5 0

2 years ago

Which of the following are reasons used in the proof that the angle-bisector construction can be used to bisect any angle? Check

Bad White [126]

The answer for apex users are:

All of the radii of a circle are congruent

CPCTC

SSS triangle congruence postulate

3 0

3 years ago

Read 2 more answers

Cylinder that have the same base area and height. The volume of the prism is given by the formula V=lwh. In the formula for the

valentina_108 [34]

Answer:

The length x width is the area so we have to replace it with the area of the cylinder.

The area of a circle is pi x radius^2

Hope this helps

Step-by-step explanation:

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2 years ago

Limx→+∞ (x-(lnx)^2) =?

expeople1 [14]

$\lim_{x\to\infty}(x-\ln(x)^2) \\\lim_{x\to\infty}(x-2\ln(x)) \\\lim_{x\to\infty}\Big(x\Big(1-\dfrac{2\ln(x)}{x}\Big)\Big) \\\lim_{x\to\infty}x\cdot\lim_{x\to\infty}\Big(1-\dfrac{2\ln(x)}{x}\Big) \\\infty\cdot\Big(\lim_{x\to\infty}(1)-\lim_{x\to\infty}\Big(\dfrac{2\ln(x)}{x}\Big)\Big) \\\infty\cdot(1-2\lim_{x\to\infty}(1/x)) \\\infty\cdot(1-0) \\\infty\cdot1=\boxed{\infty}$

Hope this helps.

3 0

3 years ago

A train goes twice as fast downhill as it can go uphill, and 2/3 feet as fast uphill as it can go on level ground. If it goes 12

Yuri [45]

Answer:

0.5hrs

Step-by-step explanation:

Let the speed downhill be $x$ ,

Speed uphill is $0.5x$ . We are told than speed uphill is $\frac{2}{3}$ the speed on flat ground. Therefore the speed on level ground will be $\frac{0.5x}{2/3}=0.75x$ .

From this info, we can obtain the actual speed, $v_g$ on level ground as:

$x=120m/h\\0.75x=v_g\\\\\therefore v_g=\frac{0.75x \times 120m/h}{x}\\v_g=90m/h$

speed, distance and time have the relation $s=d/t$ so to obtain time to cover 45miles:

$t=d/s\\=45/90\\=0.5h$

Hence it takes 0.5hrs to cover 45miles on flat ground.

4 0

3 years ago