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3 years ago

13

Susan tossed a die 996 times. which of the following would be a good estimate of the number of times she got the number 3 on the

die?

1 answer:

nignag [31]3 years ago

5 0

Answer:

i believe the answer is 332

Step-by-step explanation:

basically what i did was divide 3 and 996. when you do that it will let you know the estimate number of the number times she got number 3 on the die.

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Ilya [14]

Y = 1/8 x + b

hope this helps

6 0

2 years ago

B - 9 = 21<br> linear equations

lana66690 [7]

Answer: b=30

Step-by-step explanation: add 9 to both sides

b−9+9=21+9

b=30

3 0

3 years ago

Read 2 more answers

What’s the answer?? (SOMEONE PLEASE HELP ME)

IgorC [24]

x = 6 or x = - 1

rearrange the equation into standard form and factorise

subtract ( - 2x - 4 ) from both sides

x² - 5x - 6 = 0 ← in standard form

the factors of - 6 which sum to - 5 are - 6 and + 1

(x - 6)(x + 1) = 0

equate each factor to zero and solve for x

x - 6 = 0 ⇒ x = 6

x + 1 = 0 ⇒ x = - 1

7 0

3 years ago

Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065. New equipment is being

Ilya [14]

Answer:

Yes, the new equipment appear to be effective in reducing the variation of weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new equipment, and this sample has a standard deviation of 0.047.

Let $\sigma$ = <u><em>standard deviation of weights of new equipment.</em></u>

SO, Null Hypothesis, $H_0$ : $\sigma \geq$ 0.065 {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, $H_A$ : $\sigma$ < 0.065 {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here <u>One-sample chi-square</u> test statistics;

T.S. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, s = sample standard deviation = 0.047

n = sample of quarters = 25

So, <u><em>the test statistics</em></u> = $\frac{(25-1)\times 0.047^{2} }{0.065^{2} }$ ~ $\chi^{2}__2_4$

= 12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.

5 0

3 years ago

For which value(s) of x will the rational expression below equal zero? Check all that apply.

Ivahew [28]

Answer: D.-6 and F.3

Step-by-step explanation:

The given rational number : $\dfrac{(x-3)(x+6)}{(x+7)}$

To find : The value of x , where the rational expression becomes equal zero.

Let's check all the options :

A. 7

At x= 7 , $\dfrac{(7-3)(7+6)}{(7+7)}=\dfrac{26}{7}\neq0$

B. -7

At x= 7 , $\dfrac{(-7-3)(-7+6)}{(-7+7)}=\dfrac{10}{0}=\infty\neq0$

C. 6

At x= 6 , $\dfrac{(6-3)(6+6)}{(6+7)}=\dfrac{36}{13}\neq0$

D. -6

At x= -6 , $\dfrac{(-6-3)(-6+6)}{(-6+7)}=\dfrac{0}{1}=0$

E. -3

At x= -3 , $\dfrac{(-3-3)(-3+6)}{(-3+7)}=\dfrac{-9}{2}\neq0$

F. 3

At x= 3 , $\dfrac{(3-3)(3+6)}{(3+7)}=0$

Thus, at x= -6 and 3 , the rational expression equals to zero .

So , the correct options are : D.-6 and F.3

8 0

3 years ago

Read 2 more answers