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lesantik [10]
3 years ago
12

There is a positive correlation between the number of times the Striped Ground Cricket chirps per second and the temperature in

degrees Fahrenheit. If a scatter plot is made with the number of chirps on the horizontal axis and the trend line is found to be y = 3x + 25, then what would you predict the temperature in degrees Fahrenheit to be when there are 20 chirps per second?
-1.6
85
135
Mathematics
2 answers:
Svetllana [295]3 years ago
8 0
I think the answer is 85 im not sure
ra1l [238]3 years ago
4 0

Answer:

85 °F


Step-by-step explanation:

The trend line equation is given by  y=3x+25

Where,

  • x is the number of chirps per second, and
  • y is the temperature in degrees Fahrenheit

We want to find the temperature when the number of chirps is 20. So we plug in 20 into x and figure out y :

y=3x+25\\y=3(20)+25\\y=60+25\\y=85

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Estimate 58% of 112 using benchmark percents. Explain your answer.
vitfil [10]

Answer:

64.96

Step-by-step explanation:

The most common benchmark percents are 0\% , 10\% , 25\% , 50\% , 75\% and 100\%

We are given 58\% which is closest to 50\%.

Now we calculate 50\% \ of \ 112 which is equal to 56.

We are left with 8\% more to add.

We can say 1\% \ of \ 112 \ is\ 1.12

Therefore 8\% \ of \ 112 \ would \ be \ 1.12\times8=8.96

Now add the two.

56+8.96= 64.96

Thus 64.96 is the answer.

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3 years ago
which of the following is the equation of a line in slope intercept form for a line with a slope equal 1/4 and Y intercept at (0
andrezito [222]

Answer: the answer is A

Step-by-step explanation:

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3 years ago
Carlos drew a plan for his garden on a coordinate plane. Rose bushes are located at A(–5, 4), B(3, 4), and C(3, –5)
BartSMP [9]

Given:

A(-5,4)

B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}

so distance between A(-5,4) and B(3,4) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

So AB is 8 unit apart.

For B(3,4) and C(3,-5).

\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

so fourth bush is 8 unit left of C.

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\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}

so fourth bush 9 units below of A.

8 0
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solniwko [45]

Answer:

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8 0
3 years ago
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klemol [59]

Answer:

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Therefore the square root of -9 is 3i or -3i

3 0
3 years ago
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