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Lemur [1.5K]
3 years ago
7

PLEASE, FAST, could someone help me out, I'm a bit confused :// ​

Mathematics
1 answer:
Mariana [72]3 years ago
6 0

Answer:

=274/300

Step-by-step explanation:

-344/300=52+172=274/300

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josephine buys candy. The candy costs $14.95 per pound. She buys 0.63 pounds of candy. Hiw much does 0.63 pounds cost round your
DerKrebs [107]
Hello there!

Since you already know that for each pound of candy Josephine buys, she has to pay 14.95 dollars, you can use this to find how much she must pay if she buys 0.63 pounds of candy.

To solve this, you must multiply 14.95 and 0.63.
This would be represented by this expression:
14.95*0.63

When you simplify, you should get 9.4185.

However, the problem asks to round to the nearest cent, which would be the hundredths place. When you round 9.4185 to the nearest cent, you should get 9.42.

Therefore, Josephine pays $9.42 dollars for 0.63 pounds of candy.
3 0
4 years ago
A semicircle is drawn onto one of the shorter sides of a rectangle. The shorter side of the rectangle measures 4 centimeters. Th
velikii [3]
<h3><u>Answer</u><u>:</u></h3>

  • 8.78 cm
<h3><u>Solution</u><u>:</u></h3>

<em>We are given that :</em>

  • A semicircle is drawn onto the shorter side of rectangle.
  • Shorter side of rectangle measures 4cm. i.e; the diameter of the circle is 4cm
  • Area of the figure is 41.4 cm²

<em><u>Using </u><u>Formulas</u><u>:</u></em>

Area of rectangle:

\quad\hookrightarrow\quad{\pmb{ \mathfrak {length\times breadth }}}

Area of semicircle:

\quad\hookrightarrow\quad{\pmb{ \mathfrak{ \dfrac{\pi r^2 }{2}}}}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>length </u><u>of </u><u>longer </u><u>side </u><u>of </u><u>rectangle</u><u>!</u>

Here, we can know that the figure is composed of one rectangle and one semicircle. Therefore by combining the areas of rectangle and circle and taking the length of rectangle as a variable , we will finds its value ;

\quad\dashrightarrow\quad \sf {Area_{\tiny { total}} = Area_{\tiny {rectangle}}+ Area_{\tiny {semicircle}}}

\quad\dashrightarrow\quad \sf {A = ( l \times b ) + \dfrac{\pi r^2 }{2} }

\quad\dashrightarrow\quad \sf {41.4 =  ( l \times 4 ) +\dfrac{3.14\times 2^2}{2} }

\quad\dashrightarrow\quad \sf { 41.4= ( l \times 4 )+ \dfrac{ 3.14\times 4}{2}}

\quad\dashrightarrow\quad \sf { 41.4=( l \times 4 )+ \dfrac{12.56}{2}}

\quad\dashrightarrow\quad \sf { 41.4= (l \times 4 )+ 6.28}

\quad\dashrightarrow\quad \sf {l \times 4 = 41.4-6.28 }

\quad\dashrightarrow\quad \sf { l\times 4 = 35.12}

\quad\dashrightarrow\quad \sf { l =\dfrac{35.12}{4}}

\quad\dashrightarrow\quad \underline{\underline{\pmb{\sf {l = 8.78\:cm}}} }

8 0
2 years ago
8610+610*20+(101-30)=
Lilit [14]

Answer:

20881

Step-by-step explanation:

Simplify the expression.

=20881

Hope this helps, have a nice day/night! :D

8 0
3 years ago
Read 2 more answers
Solve the inequality C-12&gt;-16
7nadin3 [17]

Answer:

C > - 4

Step-by-step explanation:

Given

C - 12 > - 16 ( isolate C by adding 12 to both sides )

C > - 4

3 0
3 years ago
14+4k=2−2k solve for k
n200080 [17]
14+4k=2-2k
4k+2k=2-14
6k=-12
k=-12/6
k=-2


sorry if I'm wrong
7 0
4 years ago
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