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mote1985 [20]
3 years ago
11

Monica has a $1000 bond with a 5.5% coupon. Monica purchased this bond for $1025. What is the yield of this new bond?

Mathematics
2 answers:
sashaice [31]3 years ago
8 0

Answer: the answer is 5.4% APEX

arsen [322]3 years ago
6 0

Answer:

Annual return on the bond is 1000*0.055 = $55 per year  

Yield = return/price = 55/1025 ≈ 0.0537 ≈ 5.4%


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a cereal box is 18 inches by 3 inches by 12 inches. After breakfast, the box is one-third full. How many cubic inches of cereal
Nadusha1986 [10]

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Answer: 216 in ^3

Explanation:

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I hope this helped!

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3 years ago
Help plz 20 pts TOTAL 10 pts each
motikmotik

Answer:

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5 0
3 years ago
Mrs. Gomez paid $780 for a new backyard fence. A new gate cost an additional $225. The fencing was a total of 120 feet. What was
Andrews [41]

I would do it this way

$780+$225=$1005

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if you have to round up $8.38 per foot

6 0
3 years ago
What is the value of x in the equation below?
belka [17]
remember
ln(a^b)=bln(a)
ln(e)=1
so
ln(e^x)=xln(e)=x


1+2e^{x+1}=9
minus \space\ 1 \space\ both \space\ sides
2e^{x+1}=8
divide \space\ both \space\ sides \space\ by \space\ 2
e^{x+1}=4
take \space\ ln \space\ of \space\ both \space\ sides
ln(e^{x+1})=ln(4)
(x+1)ln(e)=ln(4)
x+1=ln(4)
minus \space\ 1 \space\ from \space\ both \space\ sides
x=ln(4)-1
answer \space\ is \space\ C=ln(4)-1
5 0
3 years ago
Read 2 more answers
Find the indicated conditional probability
andrezito [222]

Given:

The two way table.

To find:

The conditional probability of P(Drive to school | Senior).

Solution:

The conditional probability is defined as:

P(A|B)=\dfrac{P(A\cap B)}{P(B)}

Using this formula, we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{P(\text{Drive to school and senior})}{P(\text{Senior})}                      ...(i)

From the given two way table, we get

Drive to school and senior = 25

Senior = 25+5+5

           = 35

Total = 2+25+3+13+20+2+25+5+5

         = 100

Now,

P(\text{Drive to school and senior})=\dfrac{25}{100}

P(\text{Senior})=\dfrac{35}{100}

Substituting these values in (i), we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{\dfrac{25}{100}}{\dfrac{35}{100}}

P(\text{Drive to school }|\text{ Senior})=\dfrac{25}{35}

P(\text{Drive to school }|\text{ Senior})=0.7142857

P(\text{Drive to school }|\text{ Senior})\approx 0.71

Therefore, the required conditional probability is 0.71.

5 0
3 years ago
Read 2 more answers
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