Answer: $28
Step-by-step explanation:
The person bought 6 cakes for $8 which reduces his money by:
= 6 * 8
= -$48
He then sells them for $10 each so the money made was:
= 10 * 6
= $60
He then buys 8 more for the same price which will reduce his money by:
= 8 * 8
= -$64
He sells these 8 for $10 so the money made was:
= 8 * 10
= $80
Total money left is therefore:
= 60 + 80 - 48 - 64
= $28
Let x and y be the two integers.
The sum of the integers is x+y while the difference is x-y assuming x is larger than y.
If x+y > x-y, then
x+y > x-y
x+y-x > x-y-x
y > -y
y+y > -y+y
2y > 0
2y/2 > 0/2
y > 0
So as long as y is positive, this makes the sum greater than the difference
For example, if x = 10 and y = 2, then
x+y = 10+2 = 12
x-y = 10-2 = 8
clearly 12 > 8 is true
If y is some negative number (say y = -4), then
x+y = 10+(-4) = 10-4 = 6
x-y = 10-(-4) = 10+4 = 16
and things flip around
Saying a blanket statement "the sum of two integers is always greater than their difference" is false overall. If you require y to be positive, then it works but as that last example shows, it doesn't always work.
So to summarize things up, I'd say the answer is "no, the statement isn't true overall"
Answer:
(5, -18)
<u><em>Brainliest, please!</em></u>
Step-by-step explanation:
(12, -9)(19, 0)
x distance: 7, y distance: 9
To get the other endpoint, we must apply the opposite.
x distance: -7, y distance: -9
(12, -9)
12 - 7 = 5, -9 - 9 = -18
(5, -18)
Answer:
Add 6 to both sides
Step-by-step explanation:
order of operations acronym- PEMDAS
P= parenthesis
E= exponents
M=multiply
D= Divide
A= Add
S= subtract
No parenthesis, exponents, multiply, or divide, so skip straight to add or subtract
Add comes first so add 6 to both sides
Add 6 to both sides.
Combine like terms
-x = 4 + 6 - 3x
-x = 10 - 3x
Isolate the x, add 3x to both sides
-x (+3x) = 10 - 3x (+3x)
-x + 3x = 10
Simplify. Combine like terms
-x + 3x = 10
2x = 10
Isolate the x, divide 2 from both sides
2x/2 = 10/2
x = 10/2
x = 5
x = 5, or A is your answer
hope this helps
