Question

Divide (x^3-20x+16)/(x-4)

Answer 1

$\frac{( x^{3}-20x+16) }{(x-4)}$

Use the rational root theorem:
$a_{o}$=16, $a_{n}$=1

The dividers of $a_{o}$: 1,2,4,8,16 
The dividers of $a_{n}$: 1

Therefore, check the following rational numbers: +-$\frac{1,2,4,8,16}{1}$

$\frac{4}{1}$ is a root of the expression, so factor out x-4

Compute $\frac{ x^{3}-20x+16 }{x-4}$ to get the rest of the equation.

$\frac{(x-4)( x^{2} +4x-4)}{x-4}$

Cancel the common factor:
$x^{2}+4x-4$ is the final answer

Answer 2

Answer 1 d 2b 3b 4 a

Step-by-step explanation:

Dividing polynomials quick check goodluck 2019