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Monica [59]
4 years ago
8

Match the term with its description.

Chemistry
2 answers:
MrMuchimi4 years ago
7 0
An acid <span>is a compound that increases hydrogen ions (H+) when it is dissolved in a solution.

</span>The term alkaline is related to <span>compound that increases the hydroxide ions (OH−) when it is dissolved in a solution.
</span>
pH refers to <span>a value from 0 to 14 that is used to specify how acidic or basic a compound is when it is dissolved in water

An </span>ion is <span>an atom or molecule that has a positive or negative charge.</span>
nika2105 [10]4 years ago
3 0

Explanation:

Acid → A) A compound that increases hydrogen ions  when it is dissolved in a solution

Acids are those substance which gives hydrogen ions in their aqueous solutions.

Alkaline → C) A compound that increases the hydroxide when it is dissolved in a solution

Bases are those substance which gives hydroxide ions in their aqueous solutions.

pH → D) A value from 0 to 14 that is used to specify how acidic or basic a compound is when it is dissolved in water

The pH is the scale ranging from 0 to 14 used. This scale helps to determine the acidic or basic nature of a compound when dissolved in water.

Ion → B) An atom or molecule that has a positive or negative charge

Ion are those species of atom which caries positive or negative charge.

Positive charged atom = cation

Negative charged atom = anion

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What is the boiling point of water when 175.0 g of Na2SO4, a strong electrolyte is dissolved in 1.000 Kg of water?
liubo4ka [24]

Answer: 101.9^0C

Explanation:

Elevation in boiling point is given by:

\Delta T_b=i\times K_b\times m

\Delta T_b=T_b-T_b^0=(T_b-100)^0C = Elevation in boiling point

i= vant hoff factor = 3 (number of ions an electrolyte produce on complete dissociation)

Na_2SO_4\rightarrow 2Na^++SO_4^{2-}

K_f = freezing point constant = 0.512^0C/m

m= molality

\Delta T_b=i\times K_b\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (water)= 1.000 kg

Molar mass of solute Na_2SO_4 = 142 g/mol

Mass of solute Na_2SO_4  = 175.0 g

(T_b-100)^0C=3\times 0.512\times \frac{175.0g}{142g/mol\times 1.000kg}

T_b=101.9^0C

Thus the boiling point of water when 175.0 g of Na_2SO_4, a strong electrolyte is dissolved in 1.000 Kg of water is 101.9^0C

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