Molar Mass of CCl4= 12+4(35.5)=154 g/mol g Carbon= 45.0g/(154 g/mol)=0.292 mole
Answer:
18 liters
Explanation:
Step 1: Figure out what the formula and what you are dealing with.
- 25 degrees celcius is constant, so it is irrelevant for the mathmatical part.
- P1 = 1 atm
- P2 = 20 atm
- V1 = 360 liters
- V2 = trying to find
Note: remember the original equation is V1/P1 = V2/P2
- Step 2: Rearrange the equation to fit this problem, you should get...
V2 = V1 x P1 / P2
- Step 3: Fill our own numbers in. You should get...
360 L x 1 atm / 20 atm = 18 Liters (do the math)
- Answer = 18 Liters
- Remember to just follow the formula and fill it in with your own numbers.
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There are 0.566 moles of carbonate in sodium carbonate.
<h3>CALCULATE MOLES:</h3>
- The number of moles of carbonate (CO3) in sodium carbonate (Na2CO3) can be calculated by dividing the mass of carbonate in the compound by the molar mass of the compound.
- no. of moles of CO3 = mass of CO3 ÷ molar mass of Na2CO3
- Molar mass of Na2CO3 = 23(2) + 12 + 16(3)
- = 46 + 12 + 48 = 106g/mol
- mass of CO3 = 12 + 48 = 60g
- no. of moles of CO3 = 60/106
- no. of moles of CO3 = 0.566mol
- Therefore, there are 0.566 moles of carbonate in sodium carbonate.
Learn more about number of moles at: brainly.com/question/1542846
