The number decreases as the amount of electrons decreases
hope that helps
Answer:
D) C₄H₉OH
Explanation:
In chemistry, isomers are chemical substances with the same formula (That is, same atoms but in different structures).
For the compound C₂H₅OC₂H₅ there are 4 atoms of C, 10 atoms of H and 1 atom of O.
A) CH₃COOH
. This compound have 2 atoms of C, 4 atoms of H and 2 atoms of O. Thus, isn't an isomer.
B) C₂H₅COOCH₃. There are 4 atoms of C but 8 atoms of H and 2 atoms of O. Isn't an isomer
C) C₃H₇COCH₃. There are 5 atoms of C, 10 atoms of H and 1 atom of O. Thus, isn't an isomer
D) C₄H₉OH. Here, you have 4 atoms of C, 10 atoms of H and 1 atom of O. That means this structure is the isomer of C₂H₅OC₂H₅
Answer:
Pb²⁺(aq) --> Ni²⁺(aq)
Explanation:
The equation of the reaction is given as;
Ni(s) + Pb(NO₃)₂(aq) --> Pb(s) + Ni(NO₃)₂(aq)
In writing the ionic equation, we break the aqueous compound into ions. The solid and liquid compounds are ignored.
We have;
Pb²⁺(aq) + NO₃²⁻(aq) --> Ni²⁺(aq) + NO₃²⁻(aq)
Canceling the spectator ions;
Pb²⁺(aq) --> Ni²⁺(aq)
step one
calculate the % of oxygen
from avogadro constant
1moles = 6.02 x 10 ^23 atoms
what about 4.33 x10^22 atoms
= ( 4.33 x 10^ 22 x 1 mole ) / 6.02 10^23= 0.0719 moles
mass= 0.0719 x16= 1.1504 g
% composition is therefore= ( 1.1504/3.25) x100 = 35.40%
step two
calculate the % composition of chrorine
100- (25.42 + 35.40)=39.18%
step 3
calculate the moles of each element
that is
Na = 25.42 /23=1.1052 moles
Cl= 39.18 /35.5=1.1037moles
O= 35.40/16= 2.2125 moles
step 4
find the mole ratio by dividing each mole by 1.1037 moles
that is
Na = 1.1052/1.1037=1.001
Cl= 1.1037/1.1037= 1
0=2.2125 = 2
therefore the empirical formula= NaClO2
Answer:
In an equilibrium mixture of the three gases, PCO = PCl2 = 2.22 × 10-4 atm. The partial pressure of the product, phosgene (COCl2), is kp=(COCl2)/(CO)(Cl2) which is . So, the correct answer is 7.34.
