All categories

2 years ago

What is the standard form of the equation?

Mathematics

1 answer:

tiny-mole [99]2 years ago

4 0

$\text{The standard form a linear equation is given by the formula:}\\
Ax+By+C=0\\\\3x=2y-4\\3x-2y+4=0\Rightarrow D
$

You might be interested in

What is the relationship between the two ratios?

antoniya [11.8K]

10/14 = 5/7
30/36 = 5/6

answer
not proportional

4 0

2 years ago

Read 2 more answers

Whats the product of 6 and q

nevsk [136]

Answer:

6q or 6 * q

Step-by-step explanation:

As you do not know what the value of the variable q is, you are essentially changing it from word form to expression form.

"product" in math means multiply, so you are multiplying 6 with q.

6q is your answer.

7 0

3 years ago

Read 2 more answers

Implicit differentiation Please help

Anvisha [2.4K]

Answer:

$y''(-1) =8$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Product Rule/Basic Power Rule]: $-y - xy' - 2y' = 0$
[Algebra] Isolate y' terms: $-xy' - 2y' = y$
[Algebra] Factor y': $y'(-x - 2) = y$
[Algebra] Isolate y': $y' = \frac{y}{-x-2}$
[Algebra] Rewrite: $y' = \frac{-y}{x+2}$

Step 3: Find y

Define equation: $-xy - 2y = -4$
Factor y: $y(-x - 2) = -4$
Isolate y: $y = \frac{-4}{-x-2}$
Simplify: $y = \frac{4}{x+2}$

Step 4: Rewrite 1st Derivative

[Algebra] Substitute in y: $y' = \frac{-\frac{4}{x+2} }{x+2}$
[Algebra] Simplify: $y' = \frac{-4}{(x+2)^2}$

Step 5: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}$
[Derivative] Simplify: $y'' = \frac{8}{(x+2)^3}$

Step 6: Find Slope at Given Point

[Algebra] Substitute in x: $y''(-1) = \frac{8}{(-1+2)^3}$
[Algebra] Evaluate: $y''(-1) =8$

6 0

3 years ago

Read 2 more answers

Pls answer and u will get banliest

In-s [12.5K]

Answer:

136°

Step-by-step explanation:

Vertically opposite angles are always equal.

The opposite angle to x is 136°.

Both angles are vertically opposite angles, so they are equal.

5 0

3 years ago

Read 2 more answers

I NEED AN ANSWER ASAP PLZZZ!!!

Helen [10]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers