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joja [24]
3 years ago
12

A teacher asks students to list the math lessons they learned on nine random school days in the past month. She evaluates the st

udents’ performance on this assignment to get a general picture of how well students are taking notes. This teacher’s method is an example of?
A. systematic random sampling
B. Simple random sampling
C. Convenience sampling
D. Stratified sampling
Mathematics
1 answer:
N76 [4]3 years ago
8 0
<span>Hope this helps: C. Convenience sampling</span>
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Total of y and five divided by x
Ede4ka [16]

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5y/x

Step-by-step explanation:

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What's the measure of ABD, DBK, and KBC? Show all work.
Andrew [12]

Answer:

56.6

Step-by-step explanation:

Since BK is a bisector of ABC at B,

this implies that:

ABC = ABK + KBC

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Simplify the product using the distributive property. (-4h +2)(3h +7)
Alekssandra [29.7K]

Answer:

  A.  -12h² - 22h + 14

Step-by-step explanation:

(-4h +2)(3h +7) = -4h(3h +7) +2(3h +7) . . . . . . . (a +b)c = ac +bc

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3 years ago
The number of kilograms of water in a human body varies directly as the mass of the body. An 87​-kg person contains 58 kg of wat
katen-ka-za [31]

Answer:

50 kg water.

Step-by-step explanation:

We have been given that the number of kilograms of water in a human body varies directly as the mass of the body.

We know that two directly proportional quantities are in form y=kx, where y varies directly with x and k is constant of variation.

We are told that an 87​-kg person contains 58 kg of water. We can represent this information in an equation as:

58=k\cdot 87

Let us find the constant of variation as:

\frac{58}{87}=\frac{k\cdot 87}{87}

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The equation y=\frac{2}{3}x represents the relation between water (y) in a human body with respect to mass of the body (x).

To find the amount of water in a 75-kg person, we will substitute x=75 in our given equation and solve for y.

y=\frac{2}{3}(75)

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Therefore, there are 50 kg of water in a 75​-kg person.

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Answer:

What is it?

Step-by-step explanation:

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