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Free_Kalibri [48]
3 years ago
14

A quadrilateral has vertices (2, 0), (0, –2), (–2, 4), and (–4, 2). Which special quadrilateral is formed by connecting the midp

oints of the sides?
a.kite
b.rectangle
c.trapezoid
d.rhombus
Mathematics
1 answer:
HACTEHA [7]3 years ago
8 0
In order to know what the polygon is, you have to plot the coordinates. After plotting, it is obviously shown a form of a rectangle. After connecting the midpoints of the sides, it formed a (D) rhombus, not a kite.
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ra1l [238]

Answer:

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Step-by-step explanation:

4 0
1 year ago
Read 2 more answers
-24=5r+3r idk how to do it
sasho [114]

Answer:

r = -3

Step-by-step explanation:

Add the like terms: 8r = -24

Isolate r by dividing each side by 8: r = -24/8

Simplify: r = -3

Hope this helps

8 0
2 years ago
I really need help on this question
jekas [21]
P(t) = [ 64/ (1 + 11.e⁽⁻⁰ ⁰⁸t⁾]
In 1991, t = 1, hence:

P(t) = [ 64/ (1 + 11.e⁽⁻⁰ ⁰⁸ˣ¹⁾]  =  5.7377 billion or rounded 5.74 billion
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5 0
3 years ago
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wolverine [178]
X=14 in
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5 0
2 years ago
Find the length of the shorter leg of a right triangle if the longer leg is 7 feet more than the shorter leg and the hypotenuse
gtnhenbr [62]
You can use the pythagorean theorem.
a^{2} + b^{2} = c^{2}
Now lets write out what we know.

Shorter leg = x
Longer Leg = x + 7
Hypotenuse = x - 7

a^{2} + b^{2} = c^{2}
Now solve for x
x^{2} + (x+7)^{2} = (2x-7)^{2}
x = 28
Since you know x = 28, which is the shorter leg, you can solve for the rest by just plugging in 28 where x is located. For instance, longer let is x + 7 so 
28 + 7 = 35





6 0
3 years ago
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