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baherus [9]
3 years ago
13

(05.05) Which of the following inequalities matches the graph? (1 point)​

Mathematics
1 answer:
alexira [117]3 years ago
6 0

Answer:  Choice A.   x \le -7

=====================================================

Explanation:

Every point in the shaded region has an x coordinate that is equal to -7 or smaller.

Example points include

  • (-8, 0)
  • (-10, 2)
  • (-9, -5)

The y coordinate does not matter. All that matters is the x coordinate. The boundary line is the equation x = -7, representing all points that have x coordinate of -7. The solid boundary line says to the reader "any point on this boundary line is part of the shaded region solution set". This inclusion is due to the "or equal to" of the inequality sign.

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Answer:

(6x+4)^2=16; x=0

Step-by-step explanation:

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a trapezoid has an area of 50 square inches. The bases are 3 inches and 7 inches. What is the height of the trapezoid.
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The height of the trapezoid is 10 inches.

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In the system shown below, what are the coordinates of the solution that lies in quadrant IV?
katrin2010 [14]

Answer:

The coordinates of the solution that lies in quadrant IV are (2, -5)

Step-by-step explanation:

We have 2 equations, the first of an ellipse and the second of a circumference.

2x^2+y^2=33\\x^2+y^2+2y=19

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x^2+y^2+2y=19\\\\x^2 = 19 -y^2 -2y

So Substituting in the first equation we have

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Now we must factor the quadratic expression.

We look for two numbers that multiply as a result -5 and add them as result 4.

These numbers are -1 and 5.

Then the factors are

y^2 +4y-5 = 0\\\\(y-1)(y+5) = 0

Therefore the system solutions are:

y = 1; y = -5

In the 4th quadrant the values of x are positive and the values of y are negative.

So we take the negative value of y and substitute it into the system equation to find x

y=-5\\\\2x^2+(-5)^2=33\\\\2x^2 = 33-25\\\\2x^2 = 8\\\\x^2 = 4

x = 2, and x= -2

In the 4th quadrant the values of x are positive

So we take the positive value of x

<em><u>the coordinates of the solution that lies in quadrant IV are (2, -5)</u></em>

6 0
3 years ago
Read 2 more answers
In a 24 km race, during which each runner maintains a constant speed throughout, Alice crosses the finish line while Becky is st
mr_godi [17]

Answer:6km

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Given

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thus t=\frac{24}{V_a}=\frac{24-8}{V_b}=\frac{24-12}{V_c}

thus \frac{V_b}{V_c}=\frac{4}{3}

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