Answer:
The correct answer is 24
Step-by-step explanation:
to solve this you will need to use the pathagreom theorum
a^{2}+b^{2}=c^{2}
A= one side lenth
B= the secons side lenth
C= hypotnuse
It is helpfull to draw out the situation
you know that the latter is 25 ft, that is your hypotnuse
you also know that the 7 ft away from the base of the building is one of the side lenths, lets call it side a
so plug the numbers into the equation
7^2 + b^2 = 25 ^2
you leave b^2 alone because that is the side you are trying to find
now square 7 and 25 but leave b^2 alone
49 + b^2 = 625
now subtract 49 from both sides
b^2 = 576
now to get rid of the square of b you have to do the opposite and square root both sides removing the square of the B and giving you the answer of..........
B= 24
Hope this helped!! I tryed to explain it as simpil as possiable
<em>The slope is 7/4</em>
<em>This means that for every 7 that Y changes, X changes by 4. Also, the problem would not go through the origin of a graph.</em>
<em>Hope this helps and have a nice day.</em>
<em>-R3TR0 Z3R0 (復古零) </em>
I think the answer is C. X*4=-12+3
The equation of a circle with center (h,k) and radius r is
(x-h)²+(y-k)²=r²
so
given center is (3,-4)
(x-3)²+(y-(-4))²=r²
(x-3)²+(y+4)²=r²
find r² by subsitutiong the point taht it passes through which is (6,5)
so
(6-3)²+(5+4)²=r²
3²+9²=r²
9+81=r²
90=r²
so
(x-3)²+(y+4)²=90 is da equation
4th equation
The answer is 1/6 x (25/3m^2n^2-1)
