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2 years ago

How to round to the nearest dollar add or subtract

1 answer:

8 0

Okay Abrahammontiel1, the thing you must remember is any thing that is 5 or over must be rounded up and anything lower must be rounded down.
Example:
$2.30
since we want to round to the nearest dollar we look at the digit behind the whole dollar, which in this case is 0.3
and since it's lower that 0.5 we must round down
So it will look like this: $2

If we had a number like $4.72
we would look at the 0.7
and since it is greater that 0.5 we would round up so that it would equal $5

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The Colonel spots a campfire at a bearing N 59∘59∘ E from his current position. Sarge, who is positioned 242 feet due east of th

Rashid [163]

Answer:

i. Colonel is about 201 feet away from the fire.

ii. Sarge is about 125 feet away from the fire.

Step-by-step explanation:

Let the Colonel's location be represented by A, the Sarge's by B and that of campfire by C.

The total angle at the campfire from both the Colonel and Sarge = $59^{0}$ + $34^{0}$

= $93^{0}$

Thus,

<CAB = $90^{0}$ - $59^{0}$ = $31^{0}$

<CBA = $90^{0}$ - $34^{0}$ = $56^{0}$

Sine rule states;

$\frac{a}{Sin A}$ = $\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

i. Colonel's distance from the campfire (b), can be determined by applying the sine rule;

$\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

$\frac{b}{Sin 56^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{b}{0.8290}$ = $\frac{242}{0.9986}$

cross multiply,

b = $\frac{0.8290*242}{0.9986}$

= 200.8993

Colonel is about 201 feet away from the fire.

ii. Sarge's distance from the campfire (a), can be determined by applying the sine rule;

$\frac{a}{Sin A}$ = $\frac{c}{Sin C}$

$\frac{a}{Sin 31^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{a}{0.5150}$ = $\frac{242}{0.9986}$

cross multiply,

a = $\frac{0.5150*242}{0.9986}$

= 124.8073

Sarge is about 125 feet away from the fire.

8 0

2 years ago

Write the equation of the line that’s tangent to the given function at x=1 f(x)= two x to the third power minus four x

Aliun [14]

$f(x)=2x^3-4x$

take the derivitive to find the slope

$f'(x)=3*(2x^2)-2*(4x^0)$

$f'(x)=6x^2-4$

so at x=1, the slope is f'(1)=6(1)^2-4=6-4=2

y=mx+b

y=2x+b

find b

at x=1, f(1)=2(1)^3-4(1)=2-4=-2=y

-2=2(1)+b

-2=2+b

-4=b

equation is y=2x-4

4 0

2 years ago

Factor completely x^2-48

fredd [130]

Answer: $(x-7)(x+7)$

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below;

- Make the equation equal to zero:

$x^{2}-49=0$

-Add 49 at both sides:

$x^{2}=49$

- Now, you must take the square root of both sides of the equation, then you obtain the following roots:

$x=\sqrt{49}\\x_1=7\\x_2=-7$

- Then you have:

$x^{2}-49=$ $(x-7)(x+7)$

5 0

3 years ago

Does anyone know what the answer to this

satela [25.4K]

Answer:

60 degrees

Step-by-step explanation:

Since all three sides are the same length, all three angles must be the same size. This means the triangle is an equilateral triangle

The angles are 60 degrees

4 0

1 year ago

Read 2 more answers

Use Pascal's triangle to find the coefficient of the third term in the expansion of (a + b)2.

Alexxandr [17]

Answer:

Step-by-step explanation:

(a+b)^2

using Pascal triangle

1 1

1 2 1

1 3 3 1

so the third term in the expansion of (a+b)^2

we use

1 2 1

a^2 + 2ab+b

hence the coefficient of third term is 1

option B is collect

4 0

2 years ago