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mestny [16]
3 years ago
9

How to round to the nearest dollar add or subtract

Mathematics
1 answer:
Setler [38]3 years ago
8 0
Okay Abrahammontiel1, the thing you must remember is any thing that is 5 or over must be rounded up and anything lower must be rounded down.
Example:
$2.30
since we want to round to the nearest dollar we look at the digit behind the whole dollar, which in this case is 0.3
and since it's lower that 0.5 we must round down
So it will look like this: $2

If we had a number like $4.72
we would look at the 0.7
and since it is greater that 0.5 we would round  up so that it would equal $5

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7 0
3 years ago
2p^2 -1 =7 <br> Would appreciate some help thank you
SIZIF [17.4K]

Answer: p = 2

Step-by-step explanation:

To solve this problem, you first have to add 1 to each side of the equation, leaving you with 2p^2 = 8. Then you divide by 2 on both sides leaving you with p^2 = 4. After that, you take the square root of both sides, and because 4 is a perfect square, you get p = 2 as your final answer.

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3 years ago
Read 2 more answers
20 Point!
ludmilkaskok [199]

determinant: \sqrt{b^2-4ac}

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(b) D=16+20=36>0

D>0 means there are two real roots

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7 0
3 years ago
In the inequality 6a+4b&gt;10, what could be the possible value of a if b=2?
Arlecino [84]

We are given the following inequality:

6a+4b>10

If we replace b = 2, we get:

\begin{gathered} 6a+4(2)>10 \\ 6a+8>10 \end{gathered}

Now we solve for "a" first by subtracting 8 on both sides:

\begin{gathered} 6a+8-8>10-8 \\ 6a>2 \end{gathered}

Now we divide both sides by 6

\frac{6a}{6}>\frac{2}{6}

Simplifying:

a>\frac{1}{3}

Therefore, for b = 2, the possible values of "a" are those that are greater than 1/3

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1 year ago
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arsen [322]

Answer:

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Step-by-step explanation:

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