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4 years ago

What is the rule used to transform ΔABC to its image?

Mathematics

1 answer:

Allushta [10]4 years ago

6 0

Answer:

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y )

That is the x- coordinate remains unchanged while the y- coordinate is the negative of the original y- coordinate.

Given

A(- 3, 5 ) → A'(- 3, - 5 )

B(2, 8 ) → B'(2, - 8)

C(- 4, - 5 ) → C'(- 4, 5 )

The rule for reflection in the x- axis has been applied here → D

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3 years ago

Which of the following tools is used by engineers and scientists to document their brainstorming, sketches, design ideas, soluti

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sketches design ideas and testing results I'm pretty sure

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3 years ago

QUESTION 9! Answer all 20 questions in da quiz to get all de point in meh bank acc c:

Genrish500 [490]

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3 years ago

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The data below gives the mean price (in cents) of a liter of regular gasoline at self-service filling stations at a sample of si

bogdanovich [222]

Answer:

135.05 ; 2.762 ; (133.201, 136.899) ; (132.840, 137.260)

Step-by-step explanation:

Given the data:

Urban area Price/liter

St. John, NL 137.1

Halifax 133.6

Montreal 136.2

Regina 132.3

Saskatoon 132.2

Yellowknife 138.9

Mean = (137.1 + 133.6 + 136.2 + 132.3 + 132.2 + 138.9) / 6

= 810.3 / 6

= 135.05

Standard deviation (σ) : √Σ(X - mean)²/n-1

(137.1 - 135.05)^2 + (133.6 - 135.05)^2 + (136.2 - 135.05)^2 + (132.3 - 135.05)^2 + (132.2 - 135.05)^2+ (138.9 - 135.05)^2 = 38.135

√(38.135 / (6 - 1))

= √7.627

= 2.7617023

= 2.762

C.)

90% confidence interval of the mean :

Mean ± Zcrit * σ/√n

Zcrit at 90% = 1.64

135.05 ± 1.64 * (2.762/√6)

135.05 ± 1.64 * 1.1275817

Lower Value = (135.05 - (1.64 * 1.1275817)) = 133.201

Upper Value = (135.05 + (1.64 * 1.1275817))) = 136.899

Confidence interval = (133.201, 136.899)

D.)

95% confidence interval of the mean :

Mean ± Zcrit * σ/√n

Zcrit at 95% = 1.96

135.05 ± 1.96 * (2.762/6)

135.05 ± 1.96 * 1.1275817

Lower Value = (135.05 - (1.96 * 1.1275817)) = 132.840

Upper Value = (135.05 + (1.96 * 1.1275817)) = 137.260

Confidence interval = (132.840, 137.260)

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3 years ago

There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appr

Anton [14]

Answer: Exam A

Step-by-step explanation:

We must analyze how far are you from the mean in both cases, where the "step" that we will use to measure is the standard deviation.

In exam A, the mean is 20.5 and the standard deviation is 4.9.

If you scored a 27; then you need to see:

20.5 + 4.9 = 25.4

20.5 + 4.9 + 4.9 = 30.3

So you are within two times the standard deviation (more than the mean).

In the B exam, the mean is 1022 and the standard deviation is 214, where you scored 1209.

1022 + 214 = 1236

So in this exam, you are by one standard deviation away from the media.

With this, you can see that you did score better in exam A.

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4 years ago