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3 years ago

Which expression is equivalent to (4 + 6i)2?

2 answers:

8 0

$\bf \textit{recall that }i^2=-1\\\\
-------------------------------\\\\
(4+6i)^2\implies (4+6i)(4+6i)\implies 16+24i+24i+36i^2
\\\\\\
16+48i+36(-1)\implies 16+48i-36\implies -20+48i$

Allisa [31]3 years ago

7 0

If you mean $(4+6i)^2$ then
remember that $i=\sqrt{-1}$ and that $i^2=-1$
just treat 'i' as a variable for the expansion part
$(4+6i)^2=$ $(4+6i)(4+6i)=$ $(4*4)+(6i*4)+(4*6i)+(6i*6i)=$ $16+24i+24i+36i^2=$ $16+48i+36(-1)=$ $16+48i-36=$ $-20+48i$
you didn't give us the expressions so you will have to see which one of them is equivilent ot -20+48i

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$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

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