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Allushta [10]
3 years ago
6

Which expression is equivalent to (4 + 6i)2?

Mathematics
2 answers:
larisa86 [58]3 years ago
8 0
\bf \textit{recall that }i^2=-1\\\\
-------------------------------\\\\
(4+6i)^2\implies (4+6i)(4+6i)\implies 16+24i+24i+36i^2
\\\\\\
16+48i+36(-1)\implies 16+48i-36\implies -20+48i
Allisa [31]3 years ago
7 0
If you mean (4+6i)^2 then
remember that i=\sqrt{-1} and that i^2=-1
just treat 'i' as a variable for the expansion part
(4+6i)^2=(4+6i)(4+6i)=(4*4)+(6i*4)+(4*6i)+(6i*6i)=16+24i+24i+36i^2=16+48i+36(-1)=16+48i-36=-20+48i
you didn't give us the expressions so you will have to see which one of them is equivilent ot -20+48i
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f

(

x

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=

5

x

−

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Interval Notation:

(

−

∞

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Set-Builder Notation:

{

x

|

x

∈

R

}

The range is the set of all valid

y

values. Use the graph to find the range.

Interval Notation:

(

−

∞

,

∞

)

Set-Builder Notation:

{

y

|

y

∈

R

}

Determine the domain and range.

Domain:

(

−

∞

,

∞

)

,

{

x

|

x

∈

R

}

Range:

(

−

∞

,

∞

)

,

{

y

|

y

∈

R

}

3 0
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